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Mars2501 [29]
2 years ago
7

A system uses 2,380 J of energy to do work as 12,900 J of heat are added to the system. What is the change in internal energy of

the system?
Physics
2 answers:
Neko [114]2 years ago
9 0

The internal energy of the system is characterized by the equation U = Q + W where U is the internal energy, Q is the heat and W is work. You are given 2,380 J of energy to do work as 12,900 J of heat so add up. The internal energy is 15,280J.

worty [1.4K]2 years ago
5 0

Explanation:

The relation between change in internal energy, work and heat is as follows.

                    Q = \Delta U + W

where,       Q = heat absorbed or released by the system

                \Delta U = change in internal energy

                W = work done by or on the system

It is given that system uses 2,380 J of energy to do work. This means that work is done by the system therefore, the value of work done by the system is negative. Heat added to the system is 12,900 J.

Therefore, calculate change in internal energy as follows.

                       \Delta U = Q - W

                               = 12,900 J - (-2,380 J)

                               = (12,900 + 2,380) J

                               = 15,280 J

Thus, we can conclude that the change in internal energy of the system is 15,280 J.

       

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saveliy_v [14]

Answer:

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The spring constant is typically in range of 4900 to 29400 N/m.

So if we take the extreme case of 29400 N/m and lets say we assume an unusually, extreme case of 1 m compression, we get the value of energy added to be:

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As, you can see from the answer that even for the most extreme cases the value of mass associated with the additional energy is of very low magnitude.

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<u>d. The scale's resolution is too low to read the change in mass</u>

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Answer:

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Explanation:

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According to the law of conservation of momentum,

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2 years ago
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