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Greeley [361]
2 years ago
4

1. This energy diagram is for the thermal decomposition of solid mercury (II) oxide (also known as mercuric oxide) into liquid m

ercury and oxygen gas.
• Write a balanced equation for the reaction.
• Explain what feature is shown by the arrow labeled (a).
• Using chemical symbols and dashed lines (this can be done with type), draw what the activated complex or transition state might look like.
• Is this reaction exothermic or endothermic? Explain.

Chemistry
1 answer:
denis-greek [22]2 years ago
3 0
1) Balanced chemical equation:
         2 HgO(s) → 2 Hg(l) + O₂(g)
2) The feature indicated by line (a) is Activation energy which is the smallest amount of energy required to activate molecules in order to undergo a chemical reaction (i.e. in this case energy required to break the bond between mercury and oxygen atoms.
3) The activated complex of transition state in this case will be: Hg- - -O at which the bond between Hg and O start to be broken by heat
4) The reaction is considered as Endothermic due to the energy of products is higher than energy of reactant 
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Rank the following chemical species from lowest absolute entropy (So) (1) to highest absolute entropy (5) at 298 K?
kramer

Answer:

Rank the following chemical species from lowest absolute entropy (So) (1) to highest absolute entropy (5) at 298 K?

a. Al (s)

b. H2O (l)

c. HCN (g)

d. CH3COOH (l)

e. C2H6 (g)

Explanation:

Entropy is the measure of the degree of disorderness.

In solids, the entropy is very less compared to liquids and gases.

The entropy order is:

solids<liquids<gases

Among the given substances, water in liquid form has a strong intermolecular H-bond.

So, it has also less entropy.

Next acetic acid.

Between the gases, HCN, and ethane, ethane has more entropy due to very weak intermolecular interactions.

HCN has slight H-bonding in IT.

Hence, the entropy order is:

Al(s) < CH3COOH (l) <H2O(l) < HCN(g) < C2H6(g)

7 0
2 years ago
Select all of the correct statements pertaining to the first and second ionization energies of different elements. check all tha
sertanlavr [38]
The First Ionization energy of Nitrogen is greater (Not smaller)than that of Phosphorous. This is because going down the group (N and P are in same group) the number of shells increases, the distance of valence electrons from Nucleus increases and hence due to less interaction between nucleus and valence electrons it becomes easy to knock out the electron.

<span>The second ionization energy of Na is larger than that of Mg because after first loss of electron Na has gained Noble Gas Configuration (Stable Configuration) and now requires greater energy to loose both second electron and Noble Gas Configuration. While Mg after second ionization attains Noble Gas Configuration hence it prices less energy.</span>
8 0
2 years ago
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Two sets of flasks are connected by a hollow copper pipe, as shown. Which set will change the temperature most quickly?
Dennis_Churaev [7]
Hmm. I'm not 100% sure but. I'm pretty sure it's A because the heated water is below and there's a hotter temp. Also because it's copper, heat will move more quickly. I'm not 100% sure, are there notes you can check?
8 0
2 years ago
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Calculate the molarity of 1.0 mol of KCl in 750 ml of solution
Vaselesa [24]

Answer:

[KCl] = 1.33 M

Explanation:

Molarity is mol /L

Mol of solute in 1 L of solution

Volume of solution is 750 mL

750 mL / 1000 = 0.750 L

1 mol / 0.750L = M → 1.33

7 0
2 years ago
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The weight percent of concentrated HClO4(aq) is 70.5% and its density is 1.67 g/mL. What is the molarity of concentrated HClO4
ollegr [7]

Answer:

[HClO₄] = 11.7M

Explanation:

First of all we need to know, that a weight percent represents, the mass of solute in 100 g of solution.

Let's convert the mass to moles → 70.5 g . 1mol/100.45 g = 0.702 moles

Now we can apply the density to calculate the volume.

Density always refers to solution → Solution density = Solution mass / Solution volume

1.67 g/mL = 100 g / Solution volume

Solution volume = 100 g / 1.67 g/mL → 59.8 mL

To determine molarity (mol/L) we must convert the mL to L

59.8 mL . 1L/1000mL = 0.0598 L

Molarity → Moles of solute in 1L of solution → 0.702 mol / 0.0598 L = 11.7M

8 0
2 years ago
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