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lana [24]
2 years ago
15

The slope of the trend line is 15. What does that mean in regard to the data of the scatterplot? Check all that apply. The slope

represents the rate of change of the data. Advertising costs increase $15,000 as sales increase by $1,000. Sales increase $15,000 as ads increase by $1,000. A positive slope infers a negative correlation. A positive slope infers a positive correlation.'

Mathematics
2 answers:
Dvinal [7]2 years ago
7 0
Without the graph, we can't be 100% certain. However, it makes sense that the sales increase by $15,000 as the ads increase by $1000. It is always the change in the vertical axis over the change in the horizontal axis.

A positive slope is always a positive correlation.
tigry1 [53]2 years ago
7 0

1. The slope represents the rate of change of the data.

3. Sales increase $15,000 as ads increase by $1,000.

5. A positive slope infers a positive correlation.

<u>*These are all correct.</u>

Guest
1 year ago
edge awnser thxs
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11. In a certain town the ratio of the number of cars to that of taxis is 15:4. If
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One month julia collected 8.4 gallons of rainwater. That month she used 5.2 gallons of rainwater to water her garden and 6.5 gal
Andru [333]

Given

One month julia collected 8.4 gallons of rainwater.

she used 5.2 gallons of rainwater to water her garden

6.5 gallons of rainwater to water flowers

Find out how much was the supply of rainwater increased or decreased by the end of the month.

To proof

As given in the question

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she used 5.2 gallons of rainwater to water her garden and 6.5 gallons of rainwater to water flowers

Total water she used in the month = 5.2 gallons + 6.5gallons

                                                         = 11.7 gallons

Let the supply of rainwater increased or decreased by the end of the month

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Hence proved



8 0
2 years ago
Read 2 more answers
6.8 Use the Normal approximation. Suppose we toss a fair coin 100 times. Use the Normal approximation to find the probability th
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Answer:

(a) The probability that proportion of heads is between 0.30 and 0.70 is 1.

(b) The probability that proportion of heads is between 0.40 and 0.65 is 0.9759.

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Let <em>X</em> = number of heads.

The probability that a head occurs in a toss of a coin is, <em>p</em> = 0.50.

The coin was tossed <em>n</em> = 100 times.

A random toss's result is independent of the other tosses.

The random variable <em>X</em> follows a Binomial distribution with parameters n = 100 and <em>p</em> = 0.50.

But the sample selected is too large and the probability of success is 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of \hat p<em> </em>(sample proportion of <em>X</em>) if the following conditions are satisfied:

  1. np ≥ 10
  2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=100\times 0.50=50>10\\n(1-p)=100\times (1-0.50)=50>10

Thus, a Normal approximation to binomial can be applied.

So,  \hat p\sim N(p,\ \frac{p(1-p)}{n})

\mu_{p}=p=0.50\\\sigma_{p}=\sqrt{\frac{p(1-p)}{n}}=0.05

(a)

Compute the probability that proportion of heads is between 0.30 and 0.70 as follows:

P(0.30

                              =P(-4

Thus, the probability that proportion of heads is between 0.30 and 0.70 is 1.

(b)

Compute the probability that proportion of heads is between 0.40 and 0.65 as follows:

P(0.40

                              =P(-2

Thus, the probability that proportion of heads is between 0.40 and 0.65 is 0.9759.

6 0
2 years ago
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