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2 years ago

What two factors determine the energy production of the Hoover Dam

2 answers:

swat322 years ago

6 0

Mar 28, 2011 · The Hoover Dam generates electricity using hydropower. Hydropower is the power generated by moving water. Dams are often built on a large river, so the water falls down from the top of the dam. At the bottom of the dam, the water rotates a large turbine

Hope this helps :p

scZoUnD [109]2 years ago

4 0

Answer:

Two factors are water speed and amount of water.

Explanation:

The production of hydro electrical power can be done when the water passes from the dam to the rivers which are below dam.

Turbines which are surrounded by magnets produce the electricity when the flowing water is hit on the turbines than turbines rotates and produce electricity and turbines are present in the dam.

The energy production of the Hoover dam is based on the amount or pressure of the water if the more water is passing through the intake pipe then there is more production of energy. An artificial lake is created behind the dam.

And energy production also depends on the speed of water means if the speed of water is large then it rotate the turbine faster and increase the production.

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A 4kg block is sliding on a horizontal frictionless floor at a speed of 2.5ms and runs into a horizontal spring. The spring has

alexgriva [62]

Answer:

Explanation:

Given

mas of block $m=4\ kg$

speed of block $v=2.5\ m/s$

spring constant $k=30\ N-m$

As the mass collides with the spring its kinetic energy is converted to the Elastic Potential energy of the spring

$\frac{1}{2}mv^2=\frac{1}{2}kx^2$

$x=v\sqrt{\frac{m}{k}}$

$x=2.5\times \sqrt{\frac{4}{30}}$

$x=0.912\ m$

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2 years ago

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The speed of light in a transparent medium is 0.6 times that of its speed in vacuum. Find the refractive index of the medium.

grin007 [14]

<h2>Answer:</h2>

The refractive index is 1.66

<h2>Explanation:</h2>

The speed of light in a transparent medium is 0.6 times that of its speed in vacuum .

Refractive index of medium = speed of light in vacuum / speed of light in medium

RI = 1/0.6 = 5/3 or 1.66

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2 years ago

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Describe a situation in which different units of measure could cause confusion.

forsale [732]

When an experiment happens in the USA and the test of the world read it conversions may go wrk v and think that the experiment is false

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2 years ago

A circular coil has a 10.0 cm radius and consists of 30.0 closely wound turns of wire. an externally produced magnetic field of

IrinaVladis [17]

Magnetic flux can be calculated by the product of the magnetic field and the area that is perpendicular to the field that it penetrates. It has units of Weber or Tesla-m^2. For the first question, when there is no current in the coil, the flux would be:

ΦB = BA
A = πr^2
A = π(.1 m)^2
A = π/100 m^2

ΦB = 2.60x10^-3 T (π/100 m^2 ) ΦB = 8.17x10^-5 T-m^2 or Wb (This is only for one loop of the coil)

The inductance on the coil given the current flows in a certain direction can be calculated by the product of the total number of turns in the coil and the flux of one loop over the current passing through. We do as follows:

L = N (ΦB ) / I
L = 30 (8.17x10^-5 T-m^2) / 3.80 = 6.44x10^-4 mH

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2 years ago

A uniform rectangular plate is hanging vertically downward from a hinge that passes along its left edge. By blowing air at 11.0

Serjik [45]

Answer:

The airspeed must be 7.78 m/s for the rectangular plate kept at 30°.

Explanation:

By looking at the images below wee see that the airspeed on one side of the rectangular plate decreases the statical pressure over this side. Since over the downside, the pressure still bein the atmospheric pressure. This difference in pressure produces a lift force in the plate. The list force is the net force obtained between the difference of the forces that produce the pressure over the upside and the downside:

$F_{lift}=F_{up} - F_{dw}=0.5*p*V^2$

Where up and down relate to what movement the forces produce. And p and V are the respective air density and velocity.

When the plate is kept horizontal the lift force balance the moment due to the weight of the plate and considering that both forces act at the same point:

$F_{lift}=0.5*p*V^2=W$