The equilibrium constant for the reaction sr(s) + mg2+(aq) ⇌ sr2+(aq) + mg(s) is 2.69 × 1012 at 25°c. calculate e o for a cell m
1 answer:
You might be interested in
Answer:
Non-polar compounds: ,
,
Polar compounds: ,
Explanation:
For this question, we must start with the <u>Lewis structure</u> for each molecule and then we can do their respective analysis:
-)
In this case, we have 4 equal atoms attached to the central atom. Therefore, we have the <u>same magnitude</u> of electronegativity. Chlorine atoms have <u>different and opposite directions.</u> Therefore due to the orientation the dipole moments cancel and the <u>net dipole moment will be zero</u> and the molecule will be non-polar.
-)
In this case, we have a linear structure in which the magnitude of the dipole moment is the same, but the direction is the <u>opposite</u>. Therefore the dipole moments are canceled and the molecule will be <u>non-polar</u>.
-)
In this case, we also have a linear structure in which the magnitude of the dipole moment is the same, but the direction is the <u>opposite</u>. Therefore the dipole moments are canceled and the molecule will be <u>non-polar</u>.
-)
For this molecule, we have a <u>different atom</u>. The hydrogen atom, therefore the magnitude of one of the atoms attached to the central atom is different and the magnitude of the <u>net dipole moment will be different from zero</u> and the molecule will be <u>polar</u>.
-)
For this molecule, due to the structure of the molecule, the dipole moments of oxygens <u>will not have a totally opposite configuration</u>. Therefore, the net dipole moment will be different from zero and the molecule will be <u>polar</u>.
See figure 1 to further explanations
I hope it helps!
Answer:
The concentration of sodium chloride in an aqueous solution that is 2.23 M and that has a density of 1.01 g/mL is 12.90% by mass
Explanation:
2.23 M aqueous solution of NaCl means there are 2.23 moles of NaCl in 1000 mL of solution.
We know that density is equal to ratio of mass to volume.
Here density of solution is 1.01 g/mL.
So mass of 1000 mL solution = () g = 1010 g
molar mass of NaCl = 58.44 g/mol
So mass of 2.23 moles of NaCl = () g = 130.3 g
% by mass is ratio of mass of solute to mass of solution and then multiplied by 100.
Here solute is NaCl.
So % by mass of 2.23 M aqueous solution of NaCl = % = 12.90%