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Sever21 [200]
2 years ago
7

When θ= 0 ̊, the assembly is held at rest, and the torsional spring is untwisted. if the assembly is released and falls downward

, determine its angular velocity at the instant θ= 90 ̊. rod ab has a mass of 6 kg, and the disk c has a mass of 9 kg. note: the moment due to a torsional spring is, m = kθ; where k is the stiffness of the spring?
Physics
1 answer:
Georgia [21]2 years ago
7 0
Rod is 450mm and disk has a radius of 75mm So there is a pin holding the assembly upwards which is when Θ=0 and at the pin there is a torsional spring with constant of k=20N m/rad. One end of the rod is attached to the pin and the other is attached to the disk.


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pitot tube on an airplane flying at a standard sea level reads 1.07 x 105 N/m2. What is the velocity of the airplane?
Allushta [10]

Answer:

V_infinty=98.772 m/s

Explanation:

complete question is:

The following problem assume an inviscid, incompressible flow. Also, standard sea level density and pressure are 1.23kg/m3(0.002377slug/ft3) and 1.01imes105N/m2(2116lb/ft2), respectively. A Pitot tube on an airplane flying at standard sea level reads 1.07imes105N/m2. What is the velocity of the airplane?

<u>solution:</u>

<u>given:</u>

<em>p_o=1.07*10^5 N/m^2</em>

<em>ρ_infinity=1.23 kg/m^2</em>

<em>p_infinity=1.01*10^5 N/m^2</em>

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8 0
2 years ago
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Masja [62]

As we know that

\frac{1}{d_i} + \frac{1}{d_0} = \frac{1}{f}

here we know that

d_0 = 6 cm

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so image will form on left side of lens at a distance of 15 cm

This image will be magnified and virtual image

Ray diagram is attached below here

8 0
2 years ago
You are using a rope to lift a 14.5 kg crate of fruit. Initially you are lifting the crate at 0.500 m/s. You then increase the t
lina2011 [118]

Answer:

W = 172.5 J

Explanation:

given,                                    

mass of the fruit crate = 14.5 kg

initial velocity to lift = 0.500 m/s

increase in the tension = 150 N

lift of crate = 1.15 m                  

work done by the tension = ?        

work done  = force x displacement

W = F s cos θ                                

θ = 0°                                    

W = F s x cos 0                                  

W = 150 x 1.15 x 1                

W = 172.5 J                                      

Work done on the crate by the tension force = W = 172.5 J

5 0
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5 0
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