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Crazy boy [7]
2 years ago
8

A 250 gram sample of water at the boiling point had 45.0 kj of heat added. how many grams of water were vaporized? heat of vapor

ization for water is 40.6 kj/mole.
Chemistry
1 answer:
Julli [10]2 years ago
7 0
You have 45 kJ of heat added and for every 40.6 kJ added, one mole is able to be vaporized. Find how many moles you can vaporize.

45 kJ / 40.6 kJ = 1.1 moles

Water is roughly 18 g per mole so 1.1 moles x 18 g per mol = 19.95 grams vaporized

Hope I helped!


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Concept:

<em><u>Latent Heat of Vaporization</u></em>: It is defined as the amount of heat required to change the state of mater without changing of its temperature.

From the given question, the temperature at the boiling point remained constant despite the continued addition of heat by the Bunsen burner. <em>Actually,</em> this amount of heat is used by water to break the intermolecular bonds between the water molecules in the form of latent heat that converts the liquid state of water into vapor state of water.

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A) To generate the spectrum above a source capable of producing electromagnetic radiation with an energy of 7 * 10 ^ 4 * k * J p
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More here: https://www.hasd.org/faculty/AndrewSchweitzer/spectroscopy.pdf

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