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2 years ago

14KMnO4 + 4C3H5(OH)3 7K2CO3 + 7Mn2O3 + 5CO2 + 16H2O How many moles of KMnO4 are consumed to form 0.886 moles of carbon dioxide?

1 answer:

6 0

The balanced equation is given as;
14KMnO₄ + 4C₃H₅(OH)₃ → 7K₂CO₃ + 7Mn₂O₃ + 5CO₂ + 16H₂O
14 : 5

The formed moles of CO₂ = 0.886 mol

The stoichiometric ratio between CO₂ and KMnO₄ is 5 : 14

Hence,
moles of CO₂ / moles of KMnO₄ = 5 / 14
0.886 mol / moles of KMnO₄ = 5 / 14
moles of KMnO₄ = 0.886 mol x 14 / 5
moles of KMnO₄ = 2.4808 mol

hence, consumed KMnO₄ moles = 2.4808 mol

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A sample of sodium reacts completely with 0.355 kg of chlorine, forming 585 g of sodium chloride. What mass of sodium reacted?

Kay [80]

Answer:

The mass of sodium that reacted is 230 grams

Explanation:

The balance equation of the reaction is first written .

sodium = Na

Chlorine = Cl2

sodium chloride = NaCl

2Na + Cl2 → 2NaCl

from the balance equation we calculate the molar mass involve in the reaction

Molar mass of sodium from the equation = 23(2) = 46 g

molar mass of sodium chloride from the eqaution = 23 × 2 + 35.5 × 2 = 46 + 71 = 117 g

If 46g of sodium is in 117 g of sodium chloride

? gram will be in 585 g of sodium chloride

cross multiply

46 × 585/117 = 26910/117 = 230 g

The mass of sodium that reacted is 230 grams

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2 years ago

Bonds between two atoms that are equally electronegative are _____. bonds between two atoms that are equally electronegative are

Anna [14]

Bonds of two atoms of equal electronegativity are nonpolar covalent bonds.

Your second sentence is identical to the first sentence; I'll bet the second sentence is "Bonds between two atoms that are unequally electronegative are polar covalent bonds."

4 0

2 years ago

Calculate the freezing point of a 0.08500 m aqueous solution of nano3. the molal freezing-point-depression constant of water is

Citrus2011 [14]

Depression in freezing point (Δ $T_{f}$ ) = $K_{f}$ ×m×i,
where, $K_{f}$ = cryoscopic constant = $1.86^{0} C/m$ ,
m= molality of solution = 0.0085 m
i = van't Hoff factor = 2 (For $NaNO_{3}$ )

Thus, (Δ $T_{f}$ ) = 1.86 X 0.0085 X 2 = $0.03162^{0}C$

Now, (Δ $T_{f}$ ) = $T^{0}$ - T
Here, T = freezing point of solution
$T^{0}$ = freezing point of solvent = $0^{0}C$
Thus, T = $T^{0}$ - (Δ $T_{f}$ ) = - $0.03162^{0}C$

8 0

2 years ago

Read 2 more answers

For which of the following reactions is ΔH∘rxn equal to ΔH∘f of the product(s)?You do not need to look up any values to answer t

Nutka1998 [239]

Answer:

Reactions 1, 3 and 5

Explanation:

First thing's first, let's ensure that all the reactions given are balanced. This is given as;

CO(g) + 1/2 O2(g )→ CO2(g)

Li(s) + 1/2 F2(l) → LiF(s)

C(s) + O2(g) → CO2(g)

CaCO3(g) → CaO + CO2(g)

2Li(s) + F2(g) → 2LiF(s)

For the condition to be valid;

- There is by convention 1 mol of product made. This means we eliminate reactions with more than one mole of compound formed. This eliminates reaction 5.

- The lements haveto be in their state at room temperature. Fluorine is a gas, not a liquid, at room temperature ans pressure, so 2 is not a correct answer.

This leaves us with reactions 1, 3 and 5 as the correct reactions that satisify the condition.

3 0

2 years ago

The Lewis structure for CO2 has a central The Lewis structure for C O 2 has a central blank atom attached to blank atoms.

kirza4 [7]

Answer:

See the explanation

Explanation:

1) The Lewis structure for $CO_2$ has a central Carbon atom attached to Oxygen atoms.

In the $CO_2$ we will have a structure: O=C=O the central atom "carbon" we will have 2 sigma bonds and 2 pi bonds, therefore, we have an Sp hybridization. For O we have 1 pi and 1 sigma bond, therefore, we have an Sp2 hybridization.

2) These atoms are held together by double bonds.

Again in the structure of $CO_2$ : O=C=O we only have double bonds.

3. Carbon dioxide has a Carbon dioxide has a Linear electron geometry.

Due to the double bonds we have to have a linear structure because in this geometry the atoms will be further apart from each other.

4. The carbon atom is Sp hybridized.

We will have for carbon 2 pi bonds, so we will have an Sp hybridization.

5. Carbon dioxide has two Carbon dioxide has two C(p) - O(p) π bonds and two C(sp) - O(Sp2) σ bonds.

(See figures)

Figure 1: Carbon hybridization

Figure 2: Oxygen hybridization

6 0

2 years ago