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lesya [120]
2 years ago
7

A rectangular glass block of dimensions 8.0 cm by 15.0 cm by 3.0 cm weighs 10.5 N. Calculate the minimum and the maximum pressur

e the bock can exert when it rests on a horizontal table.
---
Please answer this asap!
Physics
1 answer:
BaLLatris [955]2 years ago
3 0
The pressure can be solved using the following formula:

P = mg / A

Where: P = pressure
mg = mass * gravity = W = 10.5 N
A = l*w

Solving for A (maximum):

A = 8*3
A = 24 sq. cm

Solving for A (minimum):

A = 15*8
A = 120 sq. cm

Substituting into the first equation:

Pmax = 10.5 N / 24 sq.cm
Pmax = 0.4375 Pa

Pmin = 10.5 N / 120 sq.cm
<span>Pmin = 0.0875 Pa</span>
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Answer:

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Explanation:

The formula for velocity:

\to \overline{v}={\frac{\Delta x}{\Delta t}}

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You obtain a spectrum of an object in space. The spectrum consists of a number of sharp, bright emission lines. Is this object a
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In a series circuit, a generator (1300 Hz, 12.0 V) is connected to a 14.0- resistor, a 4.40-μF capacitor, and a 6.00-mH inductor
klemol [59]

Answer:

(a) 2.8 V

(b) 5.6 V

(c) 9.8 V

Explanation:

Given:

Frequency of the generator (f) = 1300 Hz)

Terminal voltage (V) =12.0 V

Resistance of resistor (R) = 14.0 Ω

Capacitance of capacitor (C) = 4.40 μF = 4.40 × 10⁻⁶ F

Inductance of the inductor (L) = 6.00 mH = 6.00 × 10⁻³ H

In order to find the voltages across each, we first need to find the reactance and impedance.

Reactance of the inductor is given as:

X_L=2\pi f L\\\\X_L=2\times 3.14\times 1300\times 6.00\times 10^{-3}\\\\X_L=49\ \Omega

Reactance of the capacitor is given as:

X_C=\frac{1}{2\pi fC}\\\\X_C=\frac{1}{2\times 3.14\times 1300\times 4.40\times 10^{-6}}\\\\X_C =28\ \Omega

Now, impedance is given as:

Z=\sqrt{X_L^2+X_C^2}\\\\Z=\sqrt{(49)^2+(28)^2}\\\\Z=\sqrt{3185}=56.4\ \Omega

Current across the circuit is given as:

I=\frac{V}{Z}\\\\I=\frac{12}{56.4}=0.2\ A

As resistor, capacitor and inductor are connected in series, the current across each of them is same and equal to total current in the circuit.

(a)

Voltage across the resistor is given as:

V_R=IR\\\\V_R=0.2\times 14=2.8\ V

Therefore, the voltage across resistor is 2.8 V.

(b)

Voltage across the capacitor is given as:

V_C=IX_C\\\\V_C=0.2\times 28=5.6\ V

Therefore, the voltage across the capacitor is 5.6 V.

(c)

Voltage across the inductor is given as:

V_L=IX_L\\\\V_L=0.2\times 49=9.8\ V

Therefore, the voltage across the inductor is 9.8 V.

6 0
2 years ago
A photon is scattered from an initially stationary electron within a metal. How does the frequency of the photon change upon sca
sammy [17]

Answer:

The frequency of the photon decreases upon scattering

Explanation:

Here we note that when a photon is scattered by a charged particle, it is referred to as Compton scattering.

Compton scattering results in a reduction of the energy of the photon and hence an increase in the wavelength (from λ to λ') of the photon known as Compton effect.

Therefore, since the wavelength increases, we have from

λf = λ'f' = c

f = c/λ

Where:

f and f' = The frequency of the motion of the photon before and after the scattering

c = Speed of light (constant)

We have that the frequency, f, is inversely proportional to the wavelength, λ as follows;

f = c/λ

As λ = increases, and c is constant, f decreases, therefore, the frequency of the photon decreases upon scattering.

5 0
2 years ago
How much gravitational potential energy does a 45.2 kg object have when it is 21.9m above the ground?
Blizzard [7]

Answer:

Explanation:

The formula for gravitational potential energy is

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Ep = 45.4 · 10 · 21.9 = 9,942.6 J

God is with you!!!

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1 year ago
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