The Molecule of Sodium Formate along with Formal Charges (in blue) and lone pair electrons (in red) is attached below.
Sodium Formate is an ionic compound made up of a positive part (Sodium Ion) and a polyatomic anion (Formate).
Nomenclature:
In ionic compounds the positive part is named first. As sodium ion is the positive part hence, it is named first followed by the negative part i.e. formate.
Name of Formate:
Formate ion has been derived from formic acid ( the simplest carboxylic acid). When carboxylic acids looses the acidic proton of -COOH, they are converted into Carboxylate ions.
E.g.
HCOOH (formic acid) → HCOO⁻ (formate) + H⁺
H₃CCOOH (acetic acid) → H₃CCOO⁻ (acetate) + H⁺
Formal Charges:
Formal charges are calculated using following formula,
F.C = [# of Valence e⁻] - [e⁻ in lone pairs + 1/2 # of bonding electrons]
For Oxygen:
F.C = [6] - [6 + 2/2]
F.C = [6] - [6 + 1]
F.C = 6 - 7
F.C = -1
For Sodium:
F.C = [1] - [0 + 0/2]
F.C = [1] - [0]
F.C = 1 - 0
F.C = +1
Answer: Aluminum, 
Explanation:
Density is defined as the mass contained per unit volume. It is characteristic of a substance.
Given : Mass of object = 8.44 grams
Volume of object=
Putting in the values we get:
Thus density of the object will be which matches that of aluminium.
The answer to this question would be CrO3 or H2SO4. These reagents would efficiently accomplish the transformation of 2-methyl-3-cyclopentenol into 2-methyl-3-cyclopentenone. The synthetic strategy is used for the bond forming and transformation of the molecule. The reagent required depends on the type of molecule.
Answer:
The answer to your question is T1 = 384.7 °K
Explanation:
Data
Volume 1 = V1 = 45.7 l
Temperature 1 = T1 = ?
Volume 2 = V2 = 33.9 l
Temperature 2 = T2 = 12.4°C
To solve this problem use Charles' law
V1/T1 = V2/T2
T1 = V1T2/V2
-Convert temperature to °K
T2 = 12.4 + 273 = 285.4°K
-Substitution
T1 = (45.7 x 285.4) / 33.9
-Simplification
T1 = 13042.8 / 33.9
-Result
T1 = 384.7 °K
Using the ideal gas law: PV=nRT
P is pressure; V is volume; n is the amount in moles; R=0.082; T is temperature in K.
(4.68)*(4.95)=(16.45)*(0.0821)*T
Solve for T.
T=17.15
