Question

Seawater contains approximately 1.2 ounces of salt per liter on average. How many gallons of seawater, to the nearest tenth of a gallon, would contain 1 pound of salt?

Answer 1

Answer:

3.5 gallons of sea water.

Step-by-step explanation:

Let x represent gallons of seawater.  

We have been given that seawater contains approximately 1.2 ounces of salt per liter on average.

To find the number of gallons of seawater that would contain 1 pound of salt, we will use proportions.

$\frac{1 \text{ liter}}{1.2\text{ ounce}}=\frac{x}{1\text{ pound}}$

Now, we will convert our given units as:

1 pound = 16 ounces

1 liter = 0.264172 gallons  

$\frac{\text{0.264172 gallons}}{1.2\text{ ounce}}=\frac{x}{\text{ 16 ounce}}$

$\frac{\text{0.264172 gallons}}{1.2\text{ ounce}}\times\text{ 16 ounce}=\frac{x}{\text{ 16 ounce}}\times\text{ 16 ounce}$

$\frac{\text{4.226752 gallons}}{1.2}=x$

$x=\frac{\text{4.226752 gallons}}{1.2}$

$x=3.52229\text{ gallons}\approx 3.5\text{ gallons}$

Therefore, 3.5 gallons of seawater would contain 1 pound of salt.

Answer 2

If there are 16 ounces in 1 pound, you would need 13 1/3 liters of seawater to get 1 pound of salt.

13 1/3 liters is equal to around 3.5 gallons