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2 years ago

Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?

Mathematics

1 answer:

nikitadnepr [17]2 years ago

6 0

You can start with the form
∆y(x -x1) -∆x(y -y1) = 0
Here, we have
∆y = 11-(-3) = 14
∆x = -3-1 = -4
and we can choose (x1, y1) = (1, -3). This gives
14(x -1) -(-4)(y -(-3)) = 0
14x +4y -2 = 0
All these terms have a common factor of 2 that we can remove. Adding 1 to the result puts it in standard form:

7x +2y = 1

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EXAMPLE 5 If F(x, y, z) = 4y2i + (8xy + 4e4z)j + 16ye4zk, find a function f such that ∇f = F. SOLUTION If there is such a functi

Valentin [98]

If there is such a scalar function f, then

$\dfrac{\partial f}{\partial x}=4y^2$

$\dfrac{\partial f}{\partial y}=8xy+4e^{4z}$

$\dfrac{\partial f}{\partial z}=16ye^{4z}$

Integrate both sides of the first equation with respect to x :

$f(x,y,z)=4xy^2+g(y,z)$

Differentiate both sides with respect to y :

$\dfrac{\partial f}{\partial y}=8xy+4e^{4z}=8xy+\dfrac{\partial g}{\partial y}$

$\implies\dfrac{\partial g}{\partial y}=4e^{4z}$

Integrate both sides with respect to y :

$g(y,z)=4ye^{4z}+h(z)$

Plug this into the equation above with f , then differentiate both sides with respect to z :

$f(x,y,z)=4xy^2+4ye^{4z}+h(z)$

$\dfrac{\partial f}{\partial z}=16ye^{4z}=16ye^{4z}+\dfrac{\mathrm dh}{\mathrm dz}$

$\implies\dfrac{\mathrm dh}{\mathrm dz}=0$

Integrate both sides with respect to z :

$h(z)=C$

So we end up with

$\boxed{f(x,y,z)=4xy^2+4ye^{4z}+C}$

7 0

2 years ago

a jewelry is designing a crown. the crown must have at least 45 gems using only emeralds, rubies, and diamonds. the number of ru

stepladder [879]

I'm horrible at this so I'm just guessing.
X is the variable and x means multiplication symbol.
X + (X x 3 - 1) + (X x 3 - 1) - 4) ≥ 45 is the answer I got.
The answer to that inequality would be
X ≥ 7 I think.

5 0

2 years ago

A caterer charges a $65 equipment fee to set up for a party and $9.50 per p person for food served at the party. Which of the fu

AleksAgata [21]

Answer:

The total cost function of having a party catered is f(p) = 65 + 9.50 p

Step-by-step explanation:

The equipment fee of the caterer = $65

The charge per plate = $9.50

Let, Total number of people invited in the party = p

So, the cost of plates of p people = Number of people x Per plate cost

= p x $9.50

Now, Total Catering Cost = Equipment Fee + Cost of all plates

or, Total cost = $65 + p x $9.50

Hence, the total cost function of having a party catered

is f(p) = 65 + 9.50 p.

3 0

2 years ago

Given right triangle XYZ, what is the value of tan(60°)?

Svetlanka [38]

we know that

Step $1$

in the right triangle XYZ

Applying the Pythagorean Theorem

Find the value of ZY

$XY^{2}=XZ^{2} +ZY^{2} \\ ZY^{2}=XY^{2}-XZ^{2}\\ ZY^{2}=42^{2}-21^{2}\\ ZY^{2}=1,323\\ ZY=\sqrt{1,323}\ units$

$ZY=21\sqrt{3}\ units$

Step $2$

in the right triangle XYZ

Find tan $60$ °

we know that

$tan\ 60=\frac{opposite\ side\ angle\ 60}{adjacent\ side\ angle\ 60}$

in this problem

opposite side angle $60$ is ZY

adjacent side angle $60$ is XZ

$tan\ 60=\frac{ZY}{XZ} \\ \\ tan\ 60=\frac{21\sqrt{3}}{21} \\ \\ tan\ 60=\sqrt{3}$

therefore

the answer is

$\sqrt{3}$

3 0

2 years ago

Read 2 more answers

an employee adds 160 fluid ounces of chemical to a feature that holds 120,000 gallons of water. did the employee add yhe correct

Hitman42 [59]

We are given a volume of 160 fluid ounces of chemical which is added to a container that holds 120,000 gallons of water. Assuming that the chemical has the same density as water, we just need to convert 120,000 gallons to ounces.

A conversion factor is taken from literature, 1 gallon is equivalent to 128 fluid ounces. So 160 fluid ounces is only 1.25 gallons, thus occupying minimal space in the container. The employee could add more of the chemical in the container. He can actually add 15360000 fluid ounces in total.

5 0

2 years ago