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2 years ago

What is the coefficient in the expression shown? 42+2c

2 answers:

4 0

There are two coefficients, one for x raised to the first degree, and the other for x raised to the zeroth degree (i.e. constant term).

Thus:
coefficient for the constant term : 42 (i.e. 42x^0=42).
coefficient for the linear term: 2 (i.e. 2x^1=2x)

Vikki [24]2 years ago

4 0

Answer:

The coefficient in the given expression is, 2

Step-by-step explanation:

Coefficient states that it is a multiplicative factor in some terms of a polynomial, series, or expression.

Given the expression: 42 + 2c

Here, c represents the variable.

To find the coefficient in the expression.

42 is the constant term.

2 is the coefficient of the variable c in the given expression.

Therefore, the coefficient in the given expression is, 2

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A company that manufactures small canoes has a fixed cost of $ 18 comma 000$18,000. It costs $ 120$120 to produce each canoe. Th

Scilla [17]

If the company makes 1 canoe only, then the cost is, the fixed cost plus how much it costs for the 1 canoe, or
180,000 + 1*120

if it makes 2 canoes
180,000 + 2*120
3 canoes 180,000 + 3*120
4canoes 180,000 + 4*120
x canoes 180,000 + x*120

so... we dunno what "x" is, but whatever "x" maybe, the cost ends up as 180,000 + x*120, or 180,000 + 120x

now, let's see the revenue
1 canoe 1 * 240
2 canoes 2*240
3 canoes 3*240
x canoes x*240

so.. whatever "x" maybe, the Revenue is x*240 or 240x

break-even point is when, the amount of expenses and earnings cancel each other out, or, there's no profit, but there's no loss either, same amount that's spent is also earned back

so, the break-even point occurs when Revenue = Cost

180,000 + 120x = 240x <--- solve for "x"

4 0

2 years ago

Jan began with 5/6 pound of modeling clay she used 1/5 of the clay to make decorative magnets. She divided the remaining clay in

lawyer [7]

Starting weight: 5/6 lb. Of this, Jan used 1/5, which would be (1/5)(5/6) lb,
or 1/6 lb, leaving 4/6 lb, or 2/3 lb. unused.

2/3 lb
Now divide 2/3 lb by 8 portions: ----------------- = (2/24) lb/portion, or
8 portions

1/12 lb/portion.

5 0

2 years ago

In circle S,diameter PN is drawn .If measurement arc MN=110 degrees and PS=10 then find the length of MN to the nearest tenth.Sh

Goryan [66]

Answer:

$MN=16.4\ units$

Step-by-step explanation:

step 1

Find PN

we know that

PN is a diameter

PS is a radius

$PS=10\ units$

$PN=2*PS=2*10=20\ units$

step 2

Find the measure of arc MP

$arc\ MN+arc\ MP=180\°$

$arc\ MN=110\°$

$arc\ MP=180\°-110\°=70\°$

step 3

Find the measure of angle MNP

we know that

The inscribed angle measures half that of the arc comprising

substitute the value

step 4

Find the measure of angle MPN

we know that

The inscribed angle measures half that of the arc comprising

substitute the value

step 5

Find the measure of angle NMP

The sum of the internal angles of a triangle must be equal to 180 degrees

therefore

The triangle MNP is a right triangle

step 6

Find the length MN

In the right triangle MNP

$sin($

substitute the values

$sin(55\°)=\frac{MN}{20}$

$MN=(20)sin(55\°)=16.4\ units$

7 0

2 years ago

Find the inverse of the function. y = 2x2 –4

Alex73 [517]

Answer:

The inverse function is $y=\sqrt{\frac{x+4}{2}}$

Step-by-step explanation:

The given function is $y=2x^2-4$ .

This function is only invertible on the interval, $x\ge 0$ .

To find the inverse on this interval, we interchange $x$ and $y$ .

$x=2y^2-4$

We now make $y$ the subject to get,

$x+4=2y^2$

$\Rightarrow \frac{x+4}{2}=y^2$

$\Rightarrow \pm \sqrt{\frac{x+4}{2}}=y$

But the given interval is $x\geq 0$ , This implies that, $y\geq 0$ .

$y=\sqrt{\frac{x+4}{2}}$

4 0

2 years ago

Read 2 more answers

Set up a double integral for calculating the flux of the vector field F⃗ (x,y,z)=xi⃗ +yj⃗ through the open-ended circular cylind

katrin [286]

Parameterize the cylinder (call it $S$ ) by

$\vec s(\theta,z)=\sqrt8\cos\theta\,\vec\imath+\sqrt8\sin\theta\,\vec\jmath+z\,\vec k$

with $0\le\theta\le2\pi$ and $0\le z\le9$ . Then

$\vec F(x(\theta,z),y(\theta,z),z(\theta,z))=\sqrt8\cos\theta\,\vec\imath+\sqrt8\sin\theta\,\vec\jmath$

Take the normal vector to $S$ to be

$\vec s_\theta\times\vec s_z=\sqrt8\cos\theta\,\vec\imath+\sqrt8\sin\theta\,\vec\jmath$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^9\vec F(x(\theta,z),y(\theta,z),z(\theta,z))\cdot(\vec s_\theta\times\vec s_z)\,\mathrm dz\,\mathrm d\theta$

$=\displaystyle\int_0^{2\pi}\int_0^98(\cos^2\theta+\sin^2\theta)\,\mathrm dz\,\mathrm d\theta=\boxed{144\pi}$

7 0

2 years ago