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fgiga [73]
2 years ago
13

A diver is 30 metres/99 feet underwater. the water pressure at this depth would be ______ times more than the pressure at the su

rface.
Physics
1 answer:
Leni [432]2 years ago
6 0

Answer: the pressure 30 meters underwater is about 4 times the pressure at the surface.


Explanation:


1) Pressure at the surface = Pressure of the atmosphere = 1 atm


Convert 1 atm to pascals.


1 atm = 101,325 Pa



2) Pressure 30 meters underwater = Pressure at the surface + pressure of the water



3) Pressure of the water = density of the water × g × deep


Pressure of 30 meters of water = 1000 kg/m³ × 9.81 m/s² × 30 m = 294,300 Pa



3) Pressure 30 meters underwater = 101,325 Pa + 294,300 Pa = 395,625 Pa



4) Ratio = 395,625 / 101,325 = 3,9



Therefore, the pressure 30 meters underwater is about 4 times the pressure at the surface level.

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We can find the focal length of the mirror by using the mirror equation:
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d_i is the distance of the image from the mirror

In this case, d_o = 18 cm, while d_i=-4 cm (the distance of the image should be taken as negative, because the image is to the right (behind) of the mirror, so it is virtual). If we use these data inside (1), we find the focal length of the mirror:
\frac{1}{f}= \frac{1}{18 cm}- \frac{1}{4 cm}=- \frac{7}{36 cm}
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2) The mirror is convex: in fact, for the sign convention, a concave mirror has positive focal length while a convex mirror has negative focal length. In this case, the focal length is negative, so the mirror is convex.

3) The image is virtual, because it is behind the mirror and in fact we have taken its distance from the mirror as negative.

4) The radius of curvature of a mirror is twice its focal length, so for the mirror in our problem the radius of curvature is:
r=2f=2 \cdot 5.1 cm=10.2 cm
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