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sukhopar [10]
2 years ago
12

(YOU WILL GET BRAINLIEST)Matter may be classified as a pure substance or a mixture. Where on the Venn diagram would you insert t

he term "pure substance"?
A) A
B) B
C) C
D) D

Physics
2 answers:
inessss [21]2 years ago
3 0
I think it would be B because it is matter, since it has atoms, and it contains subatomic particles, which are smaller than atoms
Klio2033 [76]2 years ago
3 0

Answer: Option (B) is the correct answer.

Explanation:

Anything that has space and occupies volume is known as matter.

A pure substance can be molecule of an element or molecule of a compound.

A molecule can have atoms of either same or different element. Whereas a compound has atoms of different elements.

For example, H_{2} is a molecule with similar atoms, that is, hydrogen element.

H_{2}O is a compound that contains hydrogen and oxygen atom.

Thus, we can conclude that pure substance contains molecule of an element or molecule of a compound.

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A ball of mass m and radius R is both sliding and spinning on a horizontal surface so that its rotational kinetic energy equals
spin [16.1K]

Answer:

\frac{v_{cm}}{\omega} = 1.122\cdot R

Explanation:

According to the statement of the problems, the following identity exists:

K_{t} = K_{r}

\frac{1}{2}\cdot m \cdot v_{cm}^{2} = 0.63\cdot m \cdot R^{2} \cdot \omega^{2}

After some algebraic handling, the ratio is obtained:

\frac{v_{cm}^{2}}{\omega^{2}}=1.26\cdot R^{2}

\frac{v_{cm}}{\omega} = 1.122\cdot R

4 0
2 years ago
If isomerization requires breaking the pi bond, what minimum energy is required for isomerization in j/mol?
aliina [53]
<span>The minimum energy required for isomerization is 267 000 J/mol 
</span>

The isomerization of cis-but-2-ene to trans-but-2-ene requires breaking of the π bond.

The bond energy of a C-C σ bond is 347 kJ/mol.

The bond energy of a C=C double bond (σ + π) is 614 kJ/mol.

So the bond energy of a π bond is (614 – 347) kJ/mol = 267 kJ/mol =
267 000 J/mol.

6 0
2 years ago
Marcus can drive his boat 24 miles down the river in 2 hours but takes 3 hours to return upstream. Find the rate of the boat in
notsponge [240]

Answer:

speed of boat as

v_b = 10 mph

river speed is given as

v_r = 2 mph

Explanation:

When boat is moving down stream then in that case net resultant speed of the boat is given as

since the boat and river is in same direction so we will have

v_1 = v_r + v_b

Now when boat moves upstream then in that case the net speed of the boat is opposite to the speed of the river

so here we have

v_2 = v_b - v_r

as we know when boat is in downstream then in that case it covers 24 miles in 2 hours

v_1 = \frac{24}{2} = 12 mph

also when it moves in upstream then it covers same distance in 3 hours of time

v_2 = \frac{24}{3} = 8 mph

v_b + v_r = 12 mph

v_b - v_r = 8 mph

so we have speed of boat as

v_b = 10 mph

river speed is given as

v_r = 2 mph

8 0
2 years ago
Read 2 more answers
A solid spherical insulator has radius r = 2.5 cm, and carries a total positive charge q = 8 × 10-10 c distributed uniformly thr
ira [324]
At r = 2R> R The expression for the electric field will be given by: (2R)^2*E=kQ. Where, k=(9*10^9)N.m/C^2, Q=(8*10^-10)C and R=0.025m.  So substituting and clearing, we have that the magnitude of the electric field will be:  E=(9*10^9)*(8*10^-10)/((2*0.025)^2)=2880 N / C.
5 0
2 years ago
A certain humidifier operates by raising water to the boiling point and then evaporating it. Every minute 30 g of water at 20◦ C
Sveta_85 [38]

Answer:

The value of total energy needed per minute for the humidifier = 77.78 KJ

Explanation:

Total energy per minute the humidifier required = Energy required to heat water to boiling point) + Energy required to convert liquid water into vapor at the boiling point) ----- (1)

Specific heat of water = 4190 \frac{J}{kg k}

The heat of vaporization is =  2256 \frac{KJ}{kg}

Mass = 0.030 kg

Energy needed to heat water to boiling point =  m c ( T_{2} - T_{1} )

Energy needed to heat water to boiling point = 0.030 × 4.19 × (100 - 20)

Energy (E_{1}) = 10.08 KJ

Energy needed to convert liquid water into vapor at the boiling point

E_{2} = 0.030 × 2256 = 67.68 KJ

Thus the total energy needed E =  E_{1} + E_{2}

E = 10.08 + 67.68

E = 77.78 KJ

This is the value of total energy needed per minute for the humidifier.

9 0
2 years ago
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