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aalyn [17]
2 years ago
4

How many moles of ncl3 contain 2.55 × 1024 chlorine atoms?

Chemistry
1 answer:
kow [346]2 years ago
8 0
When we have Cl atoms = 2.55 x 10^24 in NCl3

so,
1-  we need first to get moles of Cl = atoms / Avogadro's number

                                                          = 2.55x10^24 / 6.022 x 10^23

                                                          = 4.23 moles

2- and when NCl3 contains 3 Cl atoms :

so moles of NCl3 = moles Cl / 3 

                              = 4.23 / 3 

                              = 1.41 moles
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URGENT!! 50 Points Please Help!! Will mark brainliest!! Assignment due in 30 minutes.
dedylja [7]

a) The least number of decimal points is 0 so you should round the answer to 43.

b) The least number of significant figures is 2 so round to 7.3

c)The least number of decimal places is 1 so round to 225.7

d) The least number of significant figures is 3 so round to 92.0

e) The least number of significant figures is 3 so round to 32.4

f) The least number of decimal places is 0 so round to 104m^3

Basically, for addition and subtraction round to the least number of decimal places found in the factors, and for multiplication and division round to the least number of significant figures found in the factors.

4 0
2 years ago
A 5.0 g sample of calcium nitrate (Ca(NO3)2, M = 164) contaminated with silica (SiO2, M = 60.1) is found to contain 1.0 g calciu
zhenek [66]

Answer:

= 82%

Explanation:

Percentage purity is calculated by the formula;

% purity = (mass of pure chemical/total mass of sample) × 100

In this case;

1 mole of Ca(NO3)2 = 164 g

but; 164 g of Ca(NO3)2 = 40 g Ca

Therefore; mass of Ca(NO3)2 = 164 /40

                                                  = 4.1 g

Thus;

% purity of Ca(NO3)2 = (Mass of Ca(NO3)2/ mass of the sample)× 100

                                    = (4.1 g/ 5 g) × 100

                                    = 82%

4 0
2 years ago
Paige heated 3.00 g mercury (II) oxide (HgO, 216.59 g/mol) to form mercury (Hg, 200.59 g/mol) and oxygen (O2, 32.00 g/mol). She
stepan [7]

the balanced chemical equation for decomposition of HgO is as follows

2HgO --> 2Hg + O₂

stoichiometry of HgO to O₂ is 2:1

number of HgO moles heated are - 3.00 g / 216.59 g/mol = 0.0139 mol

according to stoichiometry of reaction -

number of O₂ moles formed = 0.0139 mol/ 2 = 0.00695 mol

mass of O₂ to be formed - 0.00695 mol x 32.00 g/mol = 0.2224 g

but the actual yield = 0.195 g

percent yield = actual yield / theoretical yield x 100 %

percent yield = 0.195 g / 0.2224 g x 100 % = 87.7 %

answer is 87.7 %

8 1
2 years ago
Read 2 more answers
The graph shows the amount of a gaseous product formed over time during two trials of a reaction. A different concentration of a
ss7ja [257]

Answer:

Trial 2, because the amount of product formed per unit time is higher.

Explanation:

Message me for extra help.

8 0
2 years ago
Read 2 more answers
How many acidic protons are there in 0.6137 g of KHP?
andreyandreev [35.5K]

0.6137 g of KHP contains 1.086 × 10^21 acidic protons.

Number of moles of KHP = mass of KHP/molar mass of KHP

Molar mass of KHP = 204.22 g/mol

Mass of KHP = 0.6137 g

Number of moles of KHP = 0.6137 g/204.22 g/mol = 0.003 moles of KHP

Now,  1 each molecule of KHP contains 1 acidic proton.

For 0.003 moles of KHP there are; 0.003 × 1 × NA

Where NA is Avogadro's number.

So;  0.003 moles of KHP contains 0.003 × 1 × 6.02 × 10^23

= 1.086 × 10^21 acidic protons.

Learn more: brainly.com/question/16672114

7 0
2 years ago
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