Torque on the wheel produced by the chain is given by,
τ= F×R= FRsin∅
here, R is the radius of the wheel = 7.70 cm=0.077 m
∅= angle between the action of force and point of contact = 90°(angle between wheel and the chain)
Substituting the values,
τ=
= 2.6 N
It is the force exerted by the chain on the wheel. Therefore, a torque of 2.6 N would be needed to stop the wheel form turning.
Answer:
Torque,
Explanation:
It is given that,
Radius of the wheel, r = 7.7 cm = 0.077 m
Force exerted on the wheel, F = 35 N
To find,
Torque needed to keep the wheel from turning.
Solution,
We know that the product of force and distance is called torque. It is given by :
So, the torque needed to keep the wheel from turning is 2.69 N-m.
Answer:
0.456033049
Explanation:
where N=mg hence
where m is mass of object, g is acceleration due to gravity whose value is taken as
,
is the coefficient of static friction and F is the applied force.
Making the subject we obtain
and substituting m for 38 Kg, g for
and 170 N for F we obtain
Therefore, the coefficient of static friction is 0.456033049
Answer:
Radius of the solenoid is 0.93 meters.
Explanation:
It is given that,
The magnetic field strength within the solenoid is given by the equation,
, t is time in seconds
The induced electric field outside the solenoid is 1.1 V/m at a distance of 2.0 m from the axis of the solenoid, x = 2 m
The electric field due to changing magnetic field is given by :
x is the distance from the axis of the solenoid
, r is the radius of the solenoid
r = 0.93 meters
So, the radius of the solenoid is 0.93 meters. Hence, this is the required solution.
Answer:
0.00066518 Nm
Explanation:
v = Velocity = 1.2 m/s
r = Distance to head = 2.3 cm
= Final angular velocity
= Initial angular velocity = 0
= Angular acceleration
t = Time taken = 2.4 s
Angular speed is given by
From equation of rotational motion
Torque
The torque of the motor is 0.00066518 Nm
Answer:
Explanation:
Given that:
For a first order instrument with a sensitivity of .4 mV/K
constant c = 25 ms = 25 × 10⁻³ s
The initial temperature = 273 K
The final temperature = 473 K
The initial volume = 0.4 mV/K × 273 K = 109.2 V
The final volume = 0.4 mV/K × 473 K = 189.2 V
the instrument’s response as a function of time for a sudden temperature increase can be computed as follows:
Let consider y to be the function of time i.e y(t).
So;
y(t) = 109.2 + (189.2 - 109.2)( 1 - )mV
y(t) = (109.2 + 80 ( 1 - )) mV
Plot the response y(t) as a function of time.
The plot of y(t) as a function of time can be seen in the diagram attached below.
What are the units for y(t)?
The unit for y(t) is mV.
Find the 90% rise time for y(t90) and the error fraction,
The 90% rise time for y(t90) is as follows:
Initially 90% of 189.2 mV = 0.9 × 189.2 mV
= 170.28 mV
170.28 mV = (109.2 + 80 ( 1 - )) mV
170.28 mV - 109.2 mV = 80 ( 1 - )) mV
61.08 mV = 80 ( 1 - )) mV
0.7635 mV = ( 1 - )) mV
t = 1.44 × 25 × 10⁻³ s
t = 0.036 s
t = 36 ms
The error fraction =
The error fraction = 0.1
The error fraction = 10%
