Question

15. Juanita has a bag of marbles. Without looking, she removes one marble, notes the color, and replaces it. She repeats this process 70 times and records the results in the table below. Red 14 Green 19 Blue 21 yellow 16

Answer 1

Your question is incomplete and here is the complete question

"Juanita has a bag of marbles. Without looking, she removes one marble, notes the color, and replaces it. She repeats this process 70 times and records the results in the table below. Red 14 Green 19 Blue 21 yellow 16 . What is probability that she will pick a blue marble on her seventy -first try ?"

Hope this is your question, if not I think you will, still be able to find an answer of your question based on this solution

Since she replaces marble every time she picks so number of total marbles for 71st try will be same 14+ 19 + 21 + 16 = 70.

Now out of total 70 marbles, 21 are blue marbles.

Probability of an event is given by formula:

$\frac{number- of-favorable-events}{total-number-of-events}$------(1)

Here number of favorable events (getting blue marble) will be 21

and total number of events (total marbles) will be 70

So on plugging these values in formula given by (1) we get

$\frac{21}{70}$

We can reduce this fraction as there is common factor 7 in 21 and 70.

So simply divide numerator and denominator by 7 as shown

$\frac{21\div 7}{70 \div 7} = \frac{3}{10}$

So thats the final probability answer for getting blue marble $\frac{3}{10}$

Hope this helps!!