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Tema [17]
2 years ago
6

A metal bar has a length of 3.0 c, a with of 3.0cm, and a height of 20cm. What volume of water, in liters would the bar displace

. Please show work
Mathematics
1 answer:
Furkat [3]2 years ago
5 0

180 cubic centimeters is the volume. And in water for liters is 0.18 liters

The work is 3*3*20=180 and there is 0.001 liters in one cubic centimeter.

Hope this helped!

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400 students were randomly sampled from a large university, and 289 said they did not get enough sleep. Conduct a hypothesis tes
melomori [17]

Answer:

The sample proportion represents a statistically significant difference from 50%

Step-by-step explanation:

Null hypothesis: The sample proportion is the same as 50%

Alternate hypothesis: The sample proportion is not the same as 50%

z = (p' - p) ÷ sqrt[p(1 - p) ÷ n]

p' is sample proportion = 289/400 = 0.7225

p is population proportion = 50% = 0.5

n is number of students sampled = 400

z = (0.7225 - 0.5) ÷ sqrt[0.5(1 - 0.5) ÷ 400] = 0.2225 ÷ 0.025 = 8.9

The test is a two-tailed test. Using a 0.01 significance level, critical value is 2.576. The region of no rejection of the null hypothesis is -2.576 and 2.576.

Conclusion:

Reject the null hypothesis because the test statistic 8.9 falls outside the region bounded by the critical values -2.576 and 2.576.

There is sufficient evidence to conclude that the sample proportion represents a statistically significant difference from 50%.

3 0
2 years ago
A basketball player that shoots 80% from the free throw line attempts two free throws. The notation for conditional probability
taurus [48]

Answer:

P(made 2nd attempt|made 1st attempt)=P(made 2nd attempt)

Step-by-step explanation:

Here given that a basketball player that shoots 80% from the free throw line attempts two free throws.

If x is the no of shoots he makes (say) then we find that each throw is independent of the other.

In other words, because he made successful first attempt, his chances for second attempt will not change

Prob for success in each attempt remains the same as 0.80

Hence I throw is independent of II throw.

When A and B are independent,then we have

P(A/B) = P(A)

Hence answer is

P(made 2nd attempt|made 1st attempt)=P(made 2nd attempt)


8 0
2 years ago
Can anyone help me with this?
Maurinko [17]

Answer:

D. -6m²n² + 10m²n + 8mn² - 10mn

Step-by-step explanation:

(-7mn + 8mn² - 8m²n²) + (10m²n + 2m²n² - 3mn)

Apply the distributive property to remove the parentheses

-7mn + 8mn² - 8m²n² + 10m²n + 2m²n² - 3mn

Combine like terms together and arrange in standard form

-7mn + 8mn² - 8m²n² + 10m²n + 2m²n² - 3mn

-8m²n² + 2m²n² + 10m²n + 8mn² - 7mn - 3mn

-6m²n² + 10m²n + 8mn² - 10mn

5 0
2 years ago
What is the GCF of the terms of the polynomial −16y4 + 12y2 – 4y?
Tresset [83]

Answer:

The GCF is - 4y

Step-by-step explanation:

Given the polynomial expression −16y4 + 12y2 – 4y?

If we carefully traverse all the terms we can factor out 4y from all the terms

=-4y(4y³-3y+1) which is similar to the original expression

Hence the greatest common factor GCF = - 4y

The Greatest Common Factor (GCF) is the largest number that will divided evenly into that number.

5 0
2 years ago
Mrs.thapa bought 150 kg of oranges.18 kg of oranges were rotten and not fit for selling.If she sold the remaining quantity of or
kogti [31]

Answer:

Rs.64

Step-by-step explanation:

<u>Amount of oranges:</u>

  • 150 kg

<u>Oranges sold:</u>

  • 150 - 18 = 132 kg

<u>Money made:</u>

  • 132* 80 = Rs. 10560

<u>Selling price of 150 kg:</u>

  • 10560/150 = Rs. 70.4

<u>Cost price:</u>

  • x+10% = 70.4
  • x*1.1= 70.4
  • x= 70.4/1.1
  • x= Rs.64
  • Cost price of oranges= Rs. 64
3 0
2 years ago
Read 2 more answers
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