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DiKsa [7]
2 years ago
10

Whipple is confused about the connection between the velocity and acceleration of the tennis ball. he decides to compare the vel

ocity of the ball and the acceleration of the ball at the apex of the ball's motion while varying the speed of the elevator. he runs the experiment for a wide range of positive speeds of the elevator and records the speed and acceleration of the ball at the top of its motion. what can whipple conclude from these data? the speed of the ball is always positive and the acceleration is always equal to −g at the instant the ball reaches the top of its motion. the speed of the ball and the acceleration are both zero when the ball reaches the top of its motion. the speed of the ball is always zero and the acceleration is always −g at the instant the ball reaches the top of its motion. the speed of the ball is always negative and the acceleration is always equal to −g at the instant the ball reaches the top of its motion.
Physics
1 answer:
tamaranim1 [39]2 years ago
7 0

The speed of the ball is always zero and the acceleration is always -g when it reaches the top of its motion. This is because when the ball is free, only gravity acts on it which is always downwards, hence g is the net acceleration and it is always negative. However the velocity does not direction change instantly, negative acceleration first slows down the ball with a positive velocity, until that point the ball keeps moving up, then the ball velocity becomes zero just before changing direction and becoming negative after which the ball will now go down along gravity. Hence the ball velocity is zero at the top (neither going up nor down). Mathematically this can be seen as velocity is the integration of acceleration.

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The brake in most cars makes use of a hydraulic system. This system consists of a fluid filled tube connected at each end to a p
Maksim231197 [3]

Answer:

The force at the brake pad = 250 N

Explanation:

The hydraulic brake system works on the Pascal's Principle for pressure transmission in fluids; the pressure applied to a fluid is transmitted undiminished in all directions.

For hydraulic systems, the pressure applied to the brake pedal is transmitted undiminished through the fluid filled tube, connected at each end to a piston, to the brake pad.

Hence, mathematically,

P(brake pedal) = P(break pad)

Pressure is given as the force applied divided by the cross sectional Area perpendicular to the direction of applied force.

P(brake pedal) = (Force applied on the brake pedal) ÷ (Cross Sectional Area of the brake pedal)

Force applied on the brake pedal = 50 N

Cross Sectional Area of the brake pedal = 3 cm²

P(brake pedal) = (50/3) = 16.67 N/cm²

P(brake pad) = P(brake pedal) = 16.67 N/cm²

P(brake pad) = (Force applied on the brake pad) ÷ (Cross Sectional Area of the brake pad)

Force applied on the brake pad = F = ?

Cross Sectional Area of the brake pad = 15 cm²

16.67 = (F/15)

F = 16.67 × 15 = 250 N

Hence, the force at the brake pad = 250 N

Hope this Helps!!!

7 0
2 years ago
If you stand next to a wall on a frictionless skateboard and push the wall with a force of 40n, how hard does the wall push on y
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The wall pushes back with the same force you exert so 40N.

to show your acceleration is .5m/s^2 use newtons second law F=ma

so plugging in numbers gives 40N=80kg*a knowing that a newton is equal 1kgm/s^2 we could write 40kg*m/s^2= 80kg*a so solving for a gives

40kg*m/s^2/80kg = a we see the kg's cancel and we're left with
(40m/s^2)/80=a which gives .5m/s^2=a
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An unstretched spring has a length of 0.30 m. When the spring is stretched to a total length of 0.60 m, it supports traveling wa
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Explanation:

Below is an attachment containing the solution

7 0
2 years ago
A girl swings on a playground swing in such a way that at her highest point she is 4.1 m from the ground, while at her lowest po
Umnica [9.8K]

Answer:

V1 =8.1 m/s

Explanation:

height at highest point (h2) = 4.1 m

height at lowest point (h1) = 0.8 m

acceleration due to gravity (g) = 9.8 m/s^{2}

from conservation of energy, the total energy at the lowest point will be the same as the total energy at the highest point. therefore

mgh1 + 0.5mV1^{2} = mgh2 + 0.5mV2^{2}

where

  • speed at highest point = V2
  • speed at lowest point = V1
  • mass of the girl and swing = m
  • at the highest point, the  speed is minimum (V1 = 0)
  • at the lowest point the speed is maximum (V2 is the maximum speed)
  • therefore the equation becomes mgh1 + 0.5mV1^{2} = mgh2

      m(gh1 + 0.5V1^{2}) = m(gh2)

      gh1 + 0.5V1^{2} = gh2

      V1 = \sqrt{\frac{gh2 - gh1}{0.5}}

now we can substitute all required values into the equation above.

V1 = \sqrt{\frac{(9.8x4.1) - (9.8x0.8)}{0.5}}

V1 = \sqrt{\frac{32.34}{0.5}}

V1 =8.1 m/s

8 0
2 years ago
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