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Vesna [10]
2 years ago
8

A supposedly silver crown is tested to determine its density. It displaces 10.7 ml of water and has a mass of 112 g. Part a coul

d the crown be made of silver? Could the crown be made of silver? No, the crown did not make of silver. The obtained density is higher than the density of silver which is 10.5 g/ml. Yes, the crown made of silver. The obtained density is equal to the density of silver which is 10.5 g/ml. No, the crown did not make of silver. The obtained density is lower than the density of silver which is 10.5 g/ml.
Chemistry
2 answers:
pickupchik [31]2 years ago
4 0

Answer:

As the silver crown is tested and it displaced 10.7mL of water with mass of crown  = 112g

Thus density = mass of metal / volume of water displaced = 112 / 10.7 = 10.5 g /mL

The actual density of silver = 10.5g / mL

Thus the crown is made up of silver as the obtained density is same as the actual density of silver

Vikentia [17]2 years ago
4 0

Density of a substance is the mass per unit volume of that substance. Density values of a substance are constant.

Given the mass of the crown = 112 g

Volume of water displaced by the crown = 10.7 mL

Density of the crown = \frac{Mass}{Volume}

                                   = \frac{112 g}{10.7 mL} =10.5\frac{g}{mL}

The crown is supposed to be made of silver. The density of silver is 10.5g/mL. The calculated value of density from given mass and volume displaced by the crown is equal to the theoretical density value of silver.

So the correct answer will be that the crown is made of silver as the estimated density is equal to that to density of silver.

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A 24.00 g sample contains 14.60 g Cl and 9.400 g B. What is the percent composition (by mass) of boron in this sample?
vaieri [72.5K]

Answer:

39.2 %

Explanation:

The following data were obtained from the question:

Mass of sample = 24 g

Mass of Cl = 14.6 g

Mass of B = 9.4 g

Percentage composition of boron =?

The percentage composition (by mass) of boron in the sample can be obtained as illustrated below:

Percentage composition of boron = mass of B /mass of sample × 100

Percentage composition of boron = 9.4/24 × 100

Percentage composition of boron = 39.2 %

Therefore, the percentage composition (by mass) of boron in the sample is 39.2 %

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How could installing new technology, such as scrubber machines, affect the factories required to install them? Name a positive a
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Installing new technology, such as scrubbers, in factories will decrease their harmful emissions. This helps improve the safety of the surrounding community and the workers. But this technology is expensive and requires time and effort to install.

Explanation:

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Annie is trying to attract her metal pencil box with a magnet from the other side of her desk. The pencil box does not move. Wha
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2 years ago
How much silver can be produced from 125g of Ag2S
rosijanka [135]

Answer:

108.9g of Silver can be produced from 125g of Ag2S

Explanation:

The compound Ag2S shows that two atoms of Silver Ag, combined with an atom of Sulphur S to form Ag2S. We can as well say the combination ration of Silver to Sulphur is 2:1

•Now we need to calculate the molecular weight of this compound by summing up the molar masses of each element in the compound.

•Molar mass of Silver Ag= 107.9g/mol

•Molar mass of Sulphur S= 32g/mol

•Molecular weight of Ag2S= (2×107.9g/mol) + 32g/mol

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•From our calculations, we know that 215.8g/mol of Ag is present in 247.8g/mol of Ag2S

If 247.8g Ag2S produced 215.8g Ag

125g Ag2S will produce xg Ag

cross multiplying we have

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3 0
2 years ago
Read 2 more answers
A geochemist in the field takes a 36.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X.
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Answer:

The solubility of X in water at 17°C is 0.110 g/mL.

Explanation:

The water of a rock pool lined with mineral crystals is a <em>saturated solution</em> of said mineral, this means the concentration of X in those 36 mL is the solubility of compound X in water at 17 °C.

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The dilution of the sample is not relevant, nor is that 500 mL volume. What's important is that 3.96 g of X form a saturated solution with 36.0 mL of water, so the solubility is:

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4 0
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