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Juli2301 [7.4K]
2 years ago
12

Convert 7.68cal/sec to Kcal/min

Chemistry
2 answers:
svp [43]2 years ago
8 0
First, you must convert 7.68cal/sec to cal/min. To do so, multiply 7.68x60(seconds, thus making a minute). 7.68x60=460.8 

Next, we must convert 460.8 cal to kcal. To do so, divide 460.8 by 1000 (460.8/1000). The result is .4608 kcal/min
sammy [17]2 years ago
6 0

Answer:

7.68 cal/sec = 0.461 kcal/min

Explanation:

Measurement = 7.68 cal/sec

Unit conversions:

1 cal (calorie) = 10⁻³ kcal (kilocalories)

1 min = 60 sec

Step 1: convert cal to kcal

7.68 cal/sec= \frac{7.68\ cal * 10^{-3} kcal}{1\ cal} *\frac{1}{sec} = 7.68*10^{-3} kcal/sec

Step 2: convert sec to min

7.68*10^{-3} kcal/sec=\frac{7.68*10^{-3} kcal}{sec} *\frac{60\ sec}{1\ min} = 0.461 kcal/min

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The answer you are looking for is d
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The mass unit associated with density is usually grams. if the volume (in ml or cm3) is multiplied by the density (g/ml or g/cm3
jok3333 [9.3K]

The weight in grams = 7.93 g

Given volume = 2.00 in^{3}

Given  density = 0.242 g/cm^{3}

We need to find the Mass(weight) in grams.

To find the weight in grams we need to keep in mind that the volume and density must use the same volume unit for cancellation. So that the volume units will cancel out, leaving only the mass units.

The unit of given volume is in^{3} and unit of volume in density is cm^{3} , so first we need to change the unit of volume from in^{3} to cm^{3} so that the volume units will cancel out, leaving only the mass units.

1 in^{3} = 16.39 cm^{3} (given conversion)

2 in^{3}\times \frac{(16.39 cm^{3})}{(1 in^{3})}

in^{3} units get cancel out leaving the cm^{3} unit.

2 in^{3} = 32.78 cm^{3}

Mass = Density X Volume.

Density = 0.242 g/cm^{3} and Volume = 32.78 cm^{3}

Mass =0.242\frac{g}{cm^{3}}\times 32.78 cm^{3}

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3 0
1 year ago
Which of the following statements best describes the properties of aluminum-28?
Contact [7]

d. When aluminum-28 undergoes beta decay, silicon-28 is produced.

Explanation:

When the nuclei of aluminium-28 decays, it produces silicon- 28:

    Aluminium    ²⁸₁₃Al

    Silicon 28      ²⁸₁₄Si

    beta particle     ⁰₋₁\beta

       

           ²⁸₁₃Al        →          ²⁸₁₄Si      +        ⁰₋₁\beta

This way, the mass and atomic number are conserved.

Conservation of mass number:

                28 = 28 + 0,  28 = 28

                 13 = 14 -1 ,       13 = 13

Learn more:

Balancing nuclear equations brainly.com/question/10094982

#learnwithBrainly

       

5 0
2 years ago
Gaseous cyclobutene undergoes a first-order reaction to form gaseous butadiene. At a particular temperature, the partial pressur
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Answer:

41.3 minutes

Explanation:

Since the reaction is a first order reaction, therefore, half life is independent of the initial concentration, or in this case, pressure.

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So, fraction of original pressure = \frac{1}{2}^2

n here is number of half life

therefore, \frac{1}{8}= \frac{1}{2}^3

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it took 124 minutes to drop pressure to 1/8 of original value, half life = 124/3= 41.3 minutes.

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Write the symbolic notation of an isotope of an element having 8 protons, 8 electrons, and 11 neutrons. Click on the “Templates”
horrorfan [7]
Attached to this answer is the format of Isotope Notation that you can use for future reference. <em>(Please open)</em>

There are 8 Protons. The Atomic Number is the same number of an element's proton.

If you can see in the format, the mass number is calculated by adding the atomic number/protons and neutrons.

Mass number = 8 + 11
Mass number = 19

The image of the final answer is attached as well.

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