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True [87]
2 years ago
7

Write the symbolic notation of an isotope of an element having 8 protons, 8 electrons, and 11 neutrons. Click on the “Templates”

button template button and make use of the "stacked super/subscript" button button for entering stackes super/subscripts for entering the mass number and atomic number of the isotope. Express your answer as an isotope.

Chemistry
1 answer:
horrorfan [7]2 years ago
5 0
Attached to this answer is the format of Isotope Notation that you can use for future reference. <em>(Please open)</em>

There are 8 Protons. The Atomic Number is the same number of an element's proton.

If you can see in the format, the mass number is calculated by adding the atomic number/protons and neutrons.

Mass number = 8 + 11
Mass number = 19

The image of the final answer is attached as well.

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At 15°C, the value of Kw is 4.5 × 10⁻¹⁵. What is the equilibrium concentration of OH⁻ at this temperature?
MaRussiya [10]
[H3O+][OH-] = 4.5 x 10^-15
[H3O+] = [OH-] = 6.7 x 10^-8 M

Explanation: do the math
5 0
2 years ago
(a) What are the possible values of l for n = 4? (Enter your answers as a comma-separated list.)
vodka [1.7K]

Answer:

(a) 0,1,2,3      (b) -3,-2,-1,0,1,2,3              (c) 6               (d) 5

Explanation:

(a) for the principal quantum number 'n', the possible values of I = 0 to n-1. Thus, if the principal quantum number 'n' =4, I = 0,1,2,3.

(b) for a given number of 'I', the possible values of ml = -I to +I. Therefore, if I =3, then ml = -3,-2,-1,0,1,2,3

(c) 'I' which is the orbital angular momentum quantum number usually has values from 0,1,2,⋯,n−1. Therefore, for n greater than or 6, t would be greater than or equal to 5. Thus, the smallest possible value of n for which I can be 6 is 6.

(d) In a 3-dimensional figure,  If the z-component of the orbital angular momentum Lz for which I=5 is measured, The possible outcomes will be:

mħ = -5ħ, -4ħ, -3ħ, -2ħ, -1ħ, 0, 1ħ, 2ħ, 3ħ, 4ħ, 5ħ.

Thus, the smallest possible l that can have a z component of 5ℏ is 5.

4 0
2 years ago
Calculate the ph of a solution that is 0.6 m in sodium acetate and 0.2 m in acetic acid. ka = 1.8 × 10−5 for acetic acid. 1. ph
Arte-miy333 [17]
      0.53 x 200ml = 106 ml of the pH 9.0 buffer + 94 ml of the pH 10 buffer gives the desired solution 
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4 0
1 year ago
What volume of 0.500 M HNO₃(aq) must completely react to neutralize 100.0 milliliters of 0.100 M KOH(aq)?
USPshnik [31]

Answer:

v = 500 milliliters

Explanation:

HNO_{3}  ⇒  H^{+}  + NO^{3-}

KOH  ⇒  K^{+}  + OH^{-}

1 H^{+} to 1 OH^{-}

\frac{0,5}{V}  = \frac{0,1}{100} \\\\v * 0,1 = 50\\v = 500 milliliters

4 0
2 years ago
A flask contains 1/3 mole of h2 and 2/3 mol of he. Compare the force on the wall per impact of h2 relative to that for he.
densk [106]

The force on the wall is actually the pressure exerted by gas molecules

Higher the pressure more the force exerted on the walls of container

The pressure depends upon the number of molecules of a gas

In a mixture of gas the pressure depends upon the mole fraction of the gas

As given the mole fraction of He is more than that of H2 therefore He will exert more pressure on the wall

The ratio of impact will be

H2 / He = 2/3 / 1/3 = 2: 1

8 0
1 year ago
Read 2 more answers
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