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Lunna [17]
2 years ago
6

You toss a ball straight up by giving it an initial upward velocity of 18 m/s. What is the velocity of the ball 0.50 s after you

released it? Define the positive y direction to be upward, the direction that you toss the ball.
Physics
1 answer:
Dmitriy789 [7]2 years ago
4 0

We know the equation of motion v = u+ at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

Acceleration = - 9.81m/s^2 . Negative means acceleration is towards center of planet Earth.

Time taken = 0.50 seconds

Initial velocity = 18 m/s

v = u+at

v = 18-9.81*0.50

   = 13.095 m/s

So velocity after 0.50 seconds is 13.095 m/s

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A plane increases its speed from 450 km/hr to 750 km/hr in 0.30 hour. What is its acceleration?
ryzh [129]

Answer:

The acceleration is found as:

a = 1000 km/h²

Explanation:

Initial speed of the plane = 450 km/h

Final speed of the plane = 750 km/h

Time taken = 0.3 h

Acceleration can be defined as the change of speed of the object divided by the time taken to bring that change

Acceleration is given as:

a=\frac{v_f-v_i}{t}

where v(f) = 750 km/h , v(i) = 450 km/h , t = 0.3 h

Substitute the values in the equation of acceleration

a= \frac{750-450}{0.3}\\a=\frac{300}{0.3}\\a=1000 km/h^2

This is the found result

5 0
2 years ago
A charged wire of negligible thickness has length 2L units and has a linear charge density λ. Consider the electric field E-vect
Stels [109]

Answer:

E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}

Explanation:

Given that

Length= 2L

Linear charge density=λ

Distance= d

K=1/(4πε)

The electric field at point P

E=2K\int_{0}^{L}\dfrac{\lambda }{r^2}dx\ sin\theta

sin\theta =\dfrac{d}{\sqrt{d^2+x^2}}

r^2=d^2+x^2

So

E=2K\lambda d\int_{0}^{L}\dfrac{dx }{(x^2+d^2)^{\frac{3}{2}}}

Now by integrating above equation

E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}

4 0
2 years ago
A charged cell phone has chemical energy stored in its battery. As you use your phone, the amount of chemical energy in the batt
Lunna [17]

Answer:

Because the chemical energy is converted to electrical enegy in the cell phone

Explanation:

This set up is not a voilation of the first law of thermodynamics because the chemical energy is not lost, it is only being transformed into electrical energy.

According to the first law of thermodynamics "energy is neither created nor destroyed but transformed from one form to another".

  • In a charged cell phone, the chemical energy is being transformed to electrical energy as you use it.
  • A phone cannot directly be powered with chemical energy.
  • The energy transformation to electrical energy makes it possible to use the phone.
  • In this process no energy is lost nor created. But simply, energy is transformed.
6 0
2 years ago
Two people are talking at a distance of 3.0 m from where you are and you measure the sound intensity as 1.1 × 10-7 W/m2. Another
ioda

Answer:

6.1875\times 10^{-8}

Explanation:

Assuming uniform spread of sound with no significant reflections or absorption. We know that sound intensity varies I=\frac {k}{r^{2}} where r is the distance

Since intensity is given then when at 3 m

1.1\times 10^{-7}= \frac {k}{3^{2}}

k=3^{2}\times 1.1\times 10^{-7}= 9.9\times 10^{-7}

Since we have the constant then at 4m

Intensity, I= \frac {9.9\times 10^{-7}}{4^{2}}=6.1875\times 10^{-8}

8 0
2 years ago
The system consists of a 20-lb disk A, 4-lb slender rod BC, and a 1-lb smooth collar C. If the disk rolls without slipping, dete
dlinn [17]

Answer:

The velocity of the collar will be 3.076 ft/s

Explanation:

Given data

weight of the disk, Wa = 20lb

weight of rod BC, Wbc = 4lb

weight of collar, Wc = 1lb

Considering the equation of equilibrium

Vb = 1.5Wbc

Wa = 1.875 Wbc

to calculate the velocity of the collar using energy conservation equation

T1 + V1 = T2 + V2

0+4(1.5 \sin 45)+2(3 \sin 45)=\frac{1}{2}\left(\frac{1}{2}\left(\frac{20}{32.2}\right)(0.8)\right)              

=>(1.875 W b c)+\frac{1}{2}\left(\frac{20}{32.2}\right)(1.5 W b c)+\frac{1}{2}\left(\frac{20}{32.2}\right)

=>(1.5 W b c) \frac{1}{2}\left\{\frac{1}{12}\left(\frac{4}{32.2}\right)(3)\right\}+\frac{1}{2}\left(\frac{1}{32.2}\right)

=>(2.598 W b c)+4(1.5 \sin 0)+2(3 \sin 0)

Wbc = 1.18rad/sec

i.e.                                    

V _c=2.598 \times 1.18

= 3.076 ft/ s

5 0
2 years ago
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