A laboratory assistant needs to prepare 35.2 liters of hydrogen at 25.0°C and 101.3 kilopascals. This is the equation for the re
action:
2HCl + Ca → H2 + CaCl2
What volume of 2.3 M hydrochloric acid is required to produce this much gas? Use the ideal gas resource.
A. 0.625 L
B. 0.876 L
C. 1.18 L
D. 1.25 L
(Some chart that I don't understand)
2HCl + Ca → H2 + CaCl2
What volume of 2.3 M hydrochloric acid is required to produce this much gas? Use the ideal gas resource.
A. 0.625 L
B. 0.876 L
C. 1.18 L
D. 1.25 L
(Some chart that I don't understand)
2 answers:
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Answer:
Ionic, metal, organic
Explanation:
In this case, we have to analyze each compound:
-)
In this compound, we have a non-metal atom (Cl) and a metal atom (Ca) . So, we will have a high electronegativity difference between these atoms, With this in mind, we will have an ionic bond. Ions can be produced:
The cation would be and the anion is
. So, we will have an <u>ionic compound.</u>
-)
In this case, we have a single atom. If we check the periodic table we will find this atom in the transition metals section (in the middle of the periodic table). So, this indicates that Cu (Copper) is a <u>metal.</u>
-)
In this molecule, we have single bonds between carbon and hydrogen. The electronegativity difference between C and H are not high enough to produce ions. So, with this in mind, we will have covalent bonds. This is the main characteristic of <u>organic compounds. </u> (See figure 1)
Answer : 0.026 moles of oxygen are in the lung
Explanation :
We can solve the given question using ideal gas law.
The equation is given below.
We have been given P = 21.1 kPa
Let us convert pressure from kPa to atm unit.
The conversion factor used here is 1 atm = 101.3 kPa.
V = 3.0 L
T = 295 K
R = 0.0821 L-atm/mol K
Let us rearrange the equation to solve for n.
0.026 moles of oxygen are in the lung