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2 years ago

How many grams of sulfur are needed to react completely with 246 g of mercury to form hgs?

Chemistry

2 answers:

iren [92.7K]2 years ago

5 0

The reaction between mercury (Hg) and sulfur (S) to form HgS is:

Hg + S ------------- HgS

Therefore: 1 mole of Hg reacts with 1 mole of S to form 1 mole of HgS

The given mass of Hg = 246 g

Atomic mass of Hg = 200.59 g/mol

# moles of Hg = 246 g/ 200.59 gmol-1 = 1.226 moles

Based on the reaction stoichiometry,

# moles of S that would react = 1.226 moles

Atomic mass of S = 32 g/mol

Therefore, mass of S = 1.226 moles*32 g/mole = 39.23 g

39.2 g of sulfur would be needed to react completely with 246 g of Hg to produce HgS

Soloha48 [4]2 years ago

5 0

39.3 grams of sulfur reacted completely with 246 grams of mercury to form HgS.

FURTHER EXPLANATION

To solve this problem, first write the balanced chemical equation for the given reaction:

Hg + S → HgS

To solve the problem, we use the stoichiometric ratios of mercury and sulfur.

First, convert the mass of mercury to moles using the molar mass (200.59 g/mol).

$moles \ Hg = 246 \ g \ Hg \times \frac{1 \ mol \ Hg}{200.59 \ g}\\\\moles \ Hg = 1.226 \ mol$

Now, determine the moles of sulfur formed using the stoichiometric ratio of sulfur and mercury which is 1:1

$moles \ S \ = 1.226 \ mol \ Hg \times \frac{`1 \ mol \ S}{1 \ mol \ Hg} \\\\moles \ S = 1.226 \ mol$

To get the mass of sulfur that reacted with mercury to form HgS, use the molar mass of sulfur (32.06 g/mol)

$mass \ of \ S = 1.226 \ mol \ S \times \frac{32.06 \ g}{1 \ mol \ S}\\\\\boxed {mass \ of \ S = 39.31 \ g}$

Since the given only has 3 significant figures, the final answer must also have the same. Therefore,

$\boxed {\boxed {mass \ of \ S = 39.3 \ g}}$

Learn More

Learn more about dimensional analysis brainly.com/question/1557970
Learn more about Limiting Reactants brainly.com/question/12979491

Keywords: stoichiometry, dimensional analysis

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Answer:

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Explanation:

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0.1800mol + 0.1800mol reactants =

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Replacing:

V1 = 23.2L

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V2 = ??

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1 year ago

In the following list, only ________ is not an example of a chemical reaction. the production of hydrogen gas from water the tar

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Answer: Option (c) is the correct answer.

Explanation:

A chemical reaction is defined as the reaction where a chemical bond will break in order to form a new bond due to the formation of a new substance.

For example, $2Na + Cl_{2} \rightarrow 2NaCl$

Here, NaCl is the new substance that is formed. A chemical reaction will always bring change in chemical composition of a substance.

The production of hydrogen gas from water, the tarnishing of a copper penny, charging a cellular phone and burning a plastic water bottle are all chemical reactions.

Whereas a reaction where no change in chemical composition of a substance takes place is known as a physical reaction.

For example, chopping a log into sawdust will change the shape but it will not bring any change in chemical composition of the substance.

Thus, we can conclude that in the following list, only chopping a log into sawdust is not an example of a chemical reaction.

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2 years ago

Copper(II) sulfide, CuS, is used in the development of aniline black dye in textile printing. What is the maximum mass of CuS wh

Naya [18.7K]

Answer:

1.82 g is the maximum mass of CuS.

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Or,

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Given :

For $CuCl_2$ :

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1 mL = 10⁻³ L

Thus, volume = 38.0×10⁻³ L

Thus, moles of $CuCl_2$ :

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The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 42.0×10⁻³ L

Thus, moles of $(NH_4)_2S$ :

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According to the given reaction:

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1 mole of $CuCl_2$ reacts with 1 mole of $(NH_4)_2S$

So,

0.019 mole of $CuCl_2$ reacts with 0.019 mole of $(NH_4)_2S$

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The formation of the product is governed by the limiting reagent. So,

1 mole of $CuCl_2$ gives 1 mole of $CuS$

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Moles of $CuS$ formed = 0.019 moles

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2 years ago

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Mila [183]

Answer:

The kinetic increases by 48.84 %

Explanation:

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v is the velocity of the object

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v is increased by 22 %. Thus, v' = 1.22 v

So, the new kinetic energy is:-

$K.E.'=\frac{1}{2}\times mv'^2=\frac{1}{2}\times m{1.22}^2=\frac{1}{2}\times mv^21.4884=1.4884K.E.$

Thus, the kinetic increases by 48.84 %

7 0

2 years ago

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