<u>Answer:</u> This illustrates law of conservation of mass.
<u>Explanation:</u>
Dalton's theory is based on mainly two laws which are law of conservation of mass and law of constant proportion.
Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.
This also means that total mass on the reactant side must be equal to the total mass on the product side.
The chemical equation for the decomposition of calcium carbonate follows:
We are given:
Mass of calcium carbonate = 100 grams
Mass of calcium oxide = 56 grams
Mass of carbon dioxide = 44 grams
Total mass on reactant side = 100 g
Total mass on product side = 56 + 44 = 100 g
As, the total mass on reactant side is equal to the total mass on product side.
Thus, this illustrates law of conservation of mass.
Answer:
83°C
Explanation:
The following were obtained from the question:
M = 40g
C = 4.2J/g°C
T1 = 91°C
T2 =?
Q = 1300J
Q = MCΔT
ΔT = Q/CM
ΔT = 1300/(4.2x40)
ΔT = 8°C
But ΔT = T1 — T2 (since the reaction involves cooling)
ΔT = T1 — T2
8 = 91 — T2
Collect like terms
8 — 91 = —T2
— 83 = —T2
Multiply through by —1
T2 = 83°C
The final temperature is 83°C
Answer:
they are pure substances: (b) and (d)
Explanation:
sulfur and cytosine are pure substances, since its composition does not changes even if the physical condition in which it is found changes.
These can not be broken down into othwer simpler substances using physical methods.
Pure substances have their own and definite characteristics.
This would support Dalton's postulates that says atoms are indivisible because there are no smaller particles than the atoms.
Explanation:
If during Thomson's cathode rays experiment, the size of the particles produced is the same as the size of the atom forming the cathode, it would perfect corroborate with Dalton's postulate.
- John Dalton believed the simplest substance of any matter is an atom.
- An atom is indivisible and cannot be broken down.
- From his atomic theory, matter does not any other smaller particles besides atom.
- If the size of the atoms of rays and that of the cathode were to be the same, this would have supported his claim.
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equilibrium constant K = 4.15 × 10⁻³
Explanation:
We have the following chemical equilibrium:
2 SO₃ (g) ⇄ 2 SO₂ (g) + O₂ (g)
equilibrium constant K = ( [SO₂]² × [O₂] ) / [SO₃]²
equilibrium constant K = ( 0.00129² × 0.106 ) / 0.00652²
equilibrium constant K = 0.414 × 10⁻² = 4.14 × 10⁻³ ≈ 4.15 × 10⁻³
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equilibrium constant
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