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Vika [28.1K]
2 years ago
13

Calculate the equilibrium constant for the reaction below if a tank was found to contain 0.106M O2, 0.00652M SO3, and 0.00129M S

O2. Calculate the equilibrium constant for the reaction below if a tank was found to contain 0.106 M O2, 0.00652 M SO3, and 0.00129 M SO2.
2 SO3 (g) ⇌ 2 SO2 (g)+O2(g)

(a)1.34 × 10^-2
(b)6.78 × 10^-2
(c)4.15 × 10^-3
(d)4.35 × 10^-2
Chemistry
1 answer:
malfutka [58]2 years ago
6 0

equilibrium constant K = 4.15 × 10⁻³

Explanation:

We have the following chemical equilibrium:

2 SO₃ (g) ⇄ 2 SO₂ (g) + O₂ (g)

equilibrium constant K = ( [SO₂]² × [O₂] ) / [SO₃]²

equilibrium constant K = ( 0.00129² × 0.106 ) / 0.00652²

equilibrium constant K = 0.414 × 10⁻² = 4.14 × 10⁻³ ≈ 4.15 × 10⁻³

Learn more about:

equilibrium constant

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So 100 g of this substance has 63.57 g of carbon, 6 g of hydrogen, 9.267 of nitrogen, and 21.17 of oxygen. I need to have them all in moles (n). You can find the molar mass (M) of each element in a periodic table.

n = m/M
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21.17 g O -> 21.17/16.00 g/mol = 1.32 moles O

So the minimum formula has this rate:

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5 0
2 years ago
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Salt solutions can be __________ to give solid salts. What word completes this sentence?
NikAS [45]

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evaporated

Explanation:

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7 0
2 years ago
Suppose you added a spoonful of sugar to hot water and another to ice-cold water. which type of water will cause the sugar to di
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an unknown metal of mass 512 g at a temperature of 15C is dropped into 325 g of water held in a 100 g aluminum container at the
ziro4ka [17]

Answer:

The specific heat capacity of the metal is 0.843J/g°C

Explanation:

Hello,

To determine the specific heat capacity of the metal, we have to work on the principle of heat loss by the metal is equals to heat gained by the water.

Heat gained by the metal = heat loss by water + calorimeter

Data,

Mass of metal (M1) = 512g

Mass of water (M2) = 325g

Initial temperature of the metal (T1) = 15°C

Initial temperature of water (T2) = 98°C

Final temperature of the mixture (T3) = 78°C

Specific heat capacity of metal (C1) = ?

Specific heat capacity of water (C2) = 4.184J/g°C

Heat loss = heat gain

M2C2(T2 - T3) = M1C1(T3 - T1)

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1359.8 × 20 = 512C1 × 63

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8 0
2 years ago
a.) The diameter of a uranium atom is 3.50 Å . Express the radius of a uranium atom in both meters and nanometers. b.) How many
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Answer:

Th answer to your question is:

a)  3.5 x10⁻¹⁰ meters; 0.35 nm

b) 6857142.86 atoms

c) Volume = 2.06 x 10⁻²³ cm³

Explanation:

a) data

Uranium atoms = 3.5A°

meters

           1 A° ----------------  1 x 10 ⁻¹⁰ m

         3.5A° ---------------  x

 x = 3.5(1 x10⁻¹⁰)/ 1 = 3.5 x10⁻¹⁰ meters

          1 A° ------------------ 0.1 nm

        3.5 A° ---------------- 0.35 nm

b) 2.4 mm

Divide 2,40 mm / uranium diameter

But, first convert 3,5A° to mm   = 3.5 x 10⁻⁷ mm

# of uranium atoms = 2.4 / 3.5 x 10⁻⁷ = 6857142.86

c) volume in cubic cm

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