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2 years ago

7

The table shows the number of songs that were downloaded and the total cost for buying the songs. What is the rate of change for

the function in the table? 2 songs for $1 $2 per song 4 songs for $1 $4 per song

2 answers:

Gennadij [26K]2 years ago

6 0

Answer:

it is $2 per song

pantera1 [17]2 years ago

3 0

Answer:

2 dollars per song

Step-by-step explanation:

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A scale model of a merry-go-round and the actual merry-go-round are similar. a. How many times greater is the base area of the a

Kipish [7]

The area ratio is the square of the linear dimension ratio. So if the merry-go-round base is circular, the area contains the square of the radius. If a polygon, the base can be divided into triangles. The area of each triangle involves the product of the base length and the height, so since both have the same change of length, the product will square the scaling ratio.
Let’s say the ratio of corresponding lengths is x:1 then the ratio of the base areas is x²:1.
The question doesn’t provide any figures.
Let’s put some in as an example. Let the actual merry-go-round be circular with a diameter of 20 feet, while the model is one foot in diameter. So the ratio of the actual ride and it’s model is 20:1. The area of the base of the actual ride is 100π sq ft. The area of the base of the model is π/4 sq ft. We expect the ratio of these areas to be 20²=400. 100π/(π/4)=400.

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2 years ago

A teacher randomly chooses a two-person leadership team from a group of four qualified students. Three of the students, Sandra,

nata0808 [166]

Answer:

What is P(A), the probability that the first student is a girl? (3/4)

What is P(A), the probability that the first student is a girl? (3/4)What is P(B), the probability that the second student is a girl? (3/4)

What is P(A), the probability that the first student is a girl? (3/4)What is P(B), the probability that the second student is a girl? (3/4)What is P(A and B), the probability that the first student is a girl and the second student is a girl? (1/2)

The probability that the first student is a girl is (3/4), likewise for the 2nd 3rd and 4th it's still (3/4). The order you pick them doesn't matter.

However, once you're looking at P(A and B) then you're fixing the first position and saying if the first student is a girl what's the probability of the second student being a girl.

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2 years ago

Kelly joins Powerhouse Gym. The cost is $30 per month and a one-time $100 joining fee. Lisa joins MegaMuscle Gym for $35 per mon

11Alexandr11 [23.1K]

it will take Lisa 11 months to have paid more than Kelly

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2 years ago

Jason ran 5/7 of the distance around the school track. Sara ran 4/5 of Jason's distance. What fraction of the total distance aro

masha68 [24]

Jason: 5/7
Sara: 4/5

Think of it this way: if the total track is a mile, and Jason runs 5/7 of it, he has run 5/7 of a mile. Then Sara runs 4/5 OF 5/7, with "of" meaning "times," so she runs 4/5 x 5/7, which gives you 20/35, which simplifies to 4/7. You can also think of Sara's distance as 80 percent of Jason's. If she runs "80 percent of the sevenths that Jason ran," that means she ran 4 out of his 5 sevenths.

7 0

2 years ago

Two football players are located at points AA and BB in a rectangular football field as shown at left. Point AA is located 5050

navik [9.2K]

Answer:

45.5 yards.

Step-by-step explanation:

We are given that two players are located at the points A and B in the rectangular field.

It is given that,

Point A is located 50 yards from the west edge and 25 yards from the south edge.

Thus, point A is given by the co-ordinate (50,25).

Also, Point B is located 12 yards from the east edge and 0 yards from the south edge.

So, point B is given by the co-ordinate (12,0).

Now, we need to find the distance between the points (50,25) and (12,0).

'The distance between two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is given by $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ '.

So, the required distance is,

Distance between players = $\sqrt{(12-50)^{2}+(0-25)^{2}}$

i.e. Distance between players = $\sqrt{(-38)^{2}+(-25)^{2}}$

i.e. Distance between players = $\sqrt{1444+625}$

i.e. Distance between players = $\sqrt{2069}$

i.e. Distance between players = 45.5 yards.

Thus, the distance between the two players located at A and B is 45.5 yards.

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2 years ago