Answer:

Explanation:
According to the statement of the problems, the following identity exists:


After some algebraic handling, the ratio is obtained:


The acceleration is the change of speed/velocity over time. Thus to calculate this you do (V1-V2)/T or (11.2-9.6)/4 or 0.4 m/s^2
Answer:
B_o = 1.013μT
Explanation:
To find B_o you take into account the formula for the emf:

where you used that A (area of the loop) is constant, an also the angle between the direction of B and the normal to A.
By applying the derivative you obtain:

when the emf is maximum the angle between B and the normal to A is zero, that is, cosθ = 1 or -1. Furthermore the cos function is 1 or -1. Hence:

hence, B_o = 1.013μT
No.
East-force can only be balanced by west-force.
North-force has no west-force in it, no matter how strong it is.
Answer:
a. the work done by the gravitational force on Block A is <u>less than</u> the work done by the gravitational force on Block B.
b. the speed of Block A is <u>equal to</u> the speed of Block B.
c. the momentum of Block A is <u>less than</u> the momentum of Block B.
Explanation:
a. The work done by the gravitational force is equal to:
w = m*g*h
where m is mass, g is the standard gravitational acceleration and h is height. Given that both blocks are released from rest at the same height, then, the bigger the mass, the bigger the work done.
b. With ramps frictionless, the final speed of the blocs is:
v = √(2*g*h)
which is independent of the mass of the blocks.
c. The momentum is calculated as follows:
momentum = m*v
Given that both bocks has the same speed, then, the bigger the mass, the bigger the momentum.