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riadik2000 [5.3K]
2 years ago
9

A) Faça o balanceamento da reação da hidroquinona com peróxido de hidrogênio. ( C6H4(OH)2(aq) + H2O2(aq) --> C6H4O2(aq) + H2O

(L) )
b) Calcule a energia liberada na reação indicada no item a) a partir das equações termoquímicas a seguir :

Chemistry
1 answer:
Vadim26 [7]2 years ago
6 0

The reaction is  (a reação é)

(C6H4(OH)2(aq) + H2O2(aq) --> C6H4O2(aq) + H2O(L) ........(i)

The other reaction given are (A outra reação dada é)

C6H4(OH)2(aq)   ---> C6H4(OH)2(aq) + H2(g)   .......(ii)   ΔH = 177 kJ

2H2O2(aq) ----> 2H2O(l) + O2(g) ..................................(iii)  ΔH = -189.3

2H2(g)  + O2(g) ----> 2H2O (l)   .....................................(iv)  ΔH =-572 kJ

We can obtain equation (i) from equation (ii), (iii) and (iv) as

[Podemos obter a equação (i) da equação (ii), (iii) e (iv) como]

equation (i) = equation (ii) + 0.5 X equation (iii) + 0.5 X equation (iv)

[equação (i) = equação (ii) + 0.5 X equação (iii) + 0.5 X equação (iv)]

So ΔH1 = ΔH(ii) + 0.5 X ΔH(iii) + 0.5 X ΔH(iv)

             = 177 + 0.5 X (-189.3) + 0.5 X(-572) = -203.65 kJ


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