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2 years ago

Consider a 20.0 % (m/v) solution. how can this be written as a conversion factor?

1 answer:

4 0

A conversion factor is a fraction or a ratio representing a relationship of two different measurement values. To write 20% m/v to a conversion factor, we need to remember that a percent is a value that represents the amount of a part per 100 units of the whole. M/v in the given value represents that the percentage is by mass per volume. So, to write it as a conversion factor, we do as follows:

20% m/v = 20 mass units / 100 volume units = 1 mass units / 5 volume units

Usually units of this are in g per L. So, it is equivalent to 1 g / 5 L

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The halogens, alkali metals, and alkaline earth metals have __________ valence electrons, respectively.

natima [27]

The valence electrons are as follows for these groups of elements:

Halogen- SEVEN (halogens are group 7 elements that need one electron for the octet rule to be achieved)

Alkali Metals - ONE (these are group one elements that lose a single electron to form an octet and cation)

Alkaline Earth Metals - TWO (group two elements that lose two electrons to form 2+ cations)

8 0

2 years ago

A gold wire has a diameter of 1.00 mm. What length of this wire contains exactly 1.00 mol of gold? (density of Au = 17.0 g/cm3)

allochka39001 [22]

Answer:

The answer to your question is 7160 cm

Explanation:

Data

diameter = 1 mm

length = ?

amount of gold = 1 mol

density = 17 g/cm³

Process

1.- Get the atomic mass of gold

Atomic mass = 197 g

then, 197g ------------ 1 mol

2.- Calculate the volume of this wire

density = mass/volume

volume = mass/density

volume = 197/17

volume = 5.7 cm³

3.- Calculate the length of the wire

Volume = πr²h

solve for h

h = volume /πr²

radius = 0.05 cm

substitution

h = 5.7/(3.14 x 0.05²)

h = 5.7 / 0.0025

h = 7159.2 cm ≈ 7160 cm

8 0

2 years ago

Read 2 more answers

Elements that do not have full outer electron shells will donate, share, or take electrons from other atoms. Choose the items th

Tamiku [17]

it´s actually Lithium and fluorine / Magnesium and Chlorine / Beryllium and Nitrogen

8 0

2 years ago

If this decay has a half life of 2.60 years, what mass of 72.5 g of sodium 22 will remain after 15.6 years

Vlad1618 [11]

Sodium-22 remain : 1.13 g

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.

Usually, radioactive elements have an unstable atomic nucleus.

General formulas used in decay:

$\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{T/t\frac{1}{2} }}}$

T = duration of decay

t 1/2 = half-life

N₀ = the number of initial radioactive atoms

Nt = the number of radioactive atoms left after decaying during T time

half-life = t 1/2=2.6 years

T=15.6 years

No=72.5 g

$\tt Nt=72.5.\dfrac{1}{2}^{15.6/2.6}\\\\Nt=72.5.\dfrac{1}{2}^6\\\\Nt=1.13~g$

8 0

2 years ago

Synthesize Information In a multistep process, cells can combine the reactants glucose (C6H12O6) and oxygen (O2) to form the pro

zloy xaker [14]

Answer:

Explanation:

In one of the process, energy is built up from scratch, in the other one, energy is liberated for use by an organism or body.

The first process deals with a metabolic reaction in which energy is liberated:

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + energy

In the above process, energy is liberated when glucose combines with oxygen. The waste products are carbon dioxide and water. This process liberates heat energy which can be used to do work.

In the reverse process:

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

This process stores energy in carbon chains as chemical energy. It is this energy that is released in the first process.

Therefore, we can see that the first process liberates energy and the reverse process stores energy.

8 0

2 years ago