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2 years ago

What is 2 hundreds + 15 tens + 6 ones

Mathematics

2 answers:

qwelly [4]2 years ago

5 0

Two one hundred is 200.
15 tens is 150.
Six ones is the same.
$200 + 150 + 6 = 456$

valentinak56 [21]2 years ago

3 0

=356// 200+150 (15x10)+6 //

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the number of common customers are 8 in number

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2 years ago

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Hello, I was wondering if someone would be able to help me with this problem I'm on. Thanks :)

koban [17]

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2 years ago

Malika charges $7.20 per hour for babysitting. She babysits 4 hours each week. She spends $10 per week and puts the rest of her

Juliette [100K]

$7.20 $28.8 $18.8 $225.6 $225.6
      4     $10     12          .25    $56.4
X___     -_____    X____ X_____ +_____
$28.8    $18.8 225.6 $56.4 $282

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2 years ago

The following table shows the number of hours some teachers in two schools expect students to spend on homework each week: Schoo

Lerok [7]

Answer:

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5

No, the box plots are not symmetric.

Step-by-step explanation:

Part A

The given data sets are

School A : 9,14,15,17,17,7,15,6,6

School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set in four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

Interquartile range of the data is

$IQR=Q_3-Q_1=16-6.5=9.5$

For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

Interquartile range of the data is

$IQR=Q_3-Q_1=15.5-8=7.5$

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data set are different.

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2 years ago

5. You deposit $300 in an account Urat pays 1.48% annual interest. What is the balance after 1 year if the

kirill [66]

Answer:

The correct option is (A) $304.47.

Step-by-step explanation:

The formula to compute the future value (FV) of an amount (A), compounded daily at an interest rate of r%, for a period of n years is:

$FV=A\times [1+\frac{r\%}{365}]^{n\times 365}$

The information provided is:

A = $300

r% = 1.48%

n = 1 year

Compute the future value as follows:

$FV=A\times [1+\frac{r\%}{365}]^{n\times 365}$

$=300\times [1+\frac{0.0148}{365}]^{365}\\\\=300\times (1.00004055)^{365}\\\\=300\times 1.014911\\\\=304.4733\\\\\approx \$304.47$

Thus, the balance after 1 year is $304.47.

The correct option is (A).

8 0

2 years ago