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klio [65]
2 years ago
4

A pile of wet mud and a pile of sandy clay are placed next to each other on a sunny day. If the temperature of each pile is equa

l and allowed to cool in the shade for a few minutes, which substance is likely to show a lower temperature and why?
A. Wet mud, because it released more heat while placed in the sun.
B. Sandy clay, because it absorbed more heat while placed in the sun.
C. Wet mud, because it requires less energy to increase its temperature.
D. Sandy clay, because it needs to release less energy to decrease its temperature.
Chemistry
2 answers:
andre [41]2 years ago
4 0

Answer: A. Wet mud, because it released more heat while placed in the sun.  

The specific heat (the amount of heat per unit mass needed to raise the temperature by one degree Celsius) of sand is typically lower than that of water. This makes the sand gets heated up faster than water. Another reason is the texture of the sand retains heat for more time than the water.

According to the above information, Wet mud, because it released more heat while placed in the sun is the correct option because sand will retain heat for long but the wet mud will release the heat because of the evaporation of water.

elixir [45]2 years ago
3 0
The answer is d hope this hepd
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The concentration of sodium chloride in an aqueous solution that is 2.23 M and that has a density of 1.01 g/mL is __________% by
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The concentration of sodium chloride in an aqueous solution that is 2.23 M and that has a density of 1.01 g/mL is 12.90% by mass

Explanation:

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Explanation:

<u>1) Data:</u>

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b) [HClO} = 0.015

c) pH = 4.64

d) pKa = ?

<u>2) Strategy:</u>

With the pH calculate [H₃O⁺], then use the equilibrium equation to calculate the equilibrium constant, Ka, and finally calculate pKa from the definition.

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