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2 years ago

A car is traveling at 118 km/h. What is its speed in mm/h?

2 answers:

7 0

We are given the speed of the car at <span>118 km/h</span>. To determine the speed in mm/h, we just need to convert the kilometer into millimeter. To do this, a conversion factor is needed. We know that,

1km=1000m
1000m = 1000000mm

Therefore,

118km/h=118000000 mm/h

Afina-wow [57]2 years ago

3 0

1km=1000m=1000000mm
118km/h=118000000 mm/h

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A hockey stick strikes a hockey puck of mass 0.17 kg. If the force exterted on the hockey puck is 35.0 N and there is a force of

GREYUIT [131]

Answer:

$a=190\ m/s^2$

Explanation:

Mass of a hockey puck, m = 0.17 kg

Force exerted by the hockey puck, F' = 35 N

The force of friction, f = 2.7 N

We need to find the acceleration of the hockey puck.

Net force, F=F'-f

F=35-2.7

F=32.3 N

Now, using second law of motion,

F = ma

a is the acceleration of the hockey puck

$a=\dfrac{F}{m}\\\\a=\dfrac{32.3}{0.17}\\\\a=190\ m/s^2$

So, the acceleration of the hockey puck is $190\ m/s^2$ .

5 0

2 years ago

Force F acts between two charges, q1 and q2, separated by a distance d. If q1 is increased to twice its original value and the d

Step2247 [10]

Okay, haven't done physics in years, let's see if I remember this.

So Coulomb's Law states that $F = k \frac{Q_1Q_2}{d^2}$ so if we double the charge on $Q_1$ and double the distance to $(2d)$ we plug these into the equation to find

<span> $F_{new} = k \frac{2Q_1Q_2}{(2d)^2}=k \frac{2Q_1Q_2}{4d^2} = \frac{2}{4} \cdot k \frac{Q_1Q_2}{d^2} = \frac{1}{2} \cdot F_{old}$ </span>

So we see the new force is exactly 1/2 of the old force so your answer should be $\frac{1}{2}F$ if I can remember my physics correctly.

9 0

2 years ago

Read 2 more answers

The actions of an employee are not attributable to the employer if the employer has not directly or indirectly encouraged the em

zepelin [54]

Answer: the answer is d

Explanation: there are not more than 10 violations within a twelve month period hope this helps

4 0

2 years ago

Calculate the volume of 19 kilograms of petrol if the density of petrol is 800 kg/m?

earnstyle [38]

Answer:

i hope this will help you :)

Explanation:

mass=19kg

density=800kg/m³

volume=?

as we know that

density=mass/volume

density×volume=mass

volume=mass/density

putting the values

volume=19kg/800kg/m³

so volume=0.02375≈0.02m³

6 0

2 years ago

The difference in heights of the liquid in the two sides of the manometer is 43.4 cm when the atmospheric pressure is 755 mm hg.

Schach [20]

The atmospheric P is greater than the P in the flask, since the Hg level is lacking down lower on the side open to the atmosphere.

43.4 cm x (10 mm / 1 cm) = 435 mm

the density of Hg is 13.6 / 0.791 = 17.2 times better than the liquid in the manometer. This means that 1 mmHg = 17.2 mm of manometer liquid.

435 mm manometer liquid x (1 mm Hg / 17.2 mm manometer liquid) = 25.3 mm Hg

The pressure in the flask is 755 - 25.3 = 729.7 mmHg.

729.7 mmHg x (1 atm / 760 mmHg ) = 0.960 atm.

4 0

2 years ago