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Artyom0805 [142]
2 years ago
6

Which of the following statements is (are) true about enzyme-catalyzed reactions? a. The reaction is faster than the same reacti

on in the absence of the enzyme. b. The free energy change is opposite from the reaction in the absence of the enzyme. c. The reaction always goes in the direction toward chemical equilibrium.
Chemistry
1 answer:
Brums [2.3K]2 years ago
5 0

Answer : The correct option is A.

Explanation :

Enzyme-catalyzed reaction :

Enzyme act as a biological catalyst and the role of catalyst is to increase the rate of chemical reaction by lowering the activation energy.

Most of the chemical reactions are slow in the absence of enzyme but in the presence of enzyme, the reaction become faster. That means the Enzyme accelerate the rate of reaction.

Therefore, the correct answer is the reaction is faster than the same reaction in the absence of the enzyme.

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Fill in the blanks with the word that best completes each statement. Scientists develop knowledge by making ------------about th
kotegsom [21]

Answer:

1. observations

2. hypothesis

3. experimentation

Explanation:

Observations are made, Hypothesies are formed from observations, and experimnets help alter and comfirm hypothesis.

3 0
2 years ago
The list below includes some of the properties of ammonia. Identify the physical properties in the list. Check all of the boxes
aleksklad [387]

Answer:

Gas at room temperature

Strong, unpleasant odor

Dissolves easily in water

Explanation:

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6 0
2 years ago
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A sample of an unknown compound was decomposed and found to be composed of 1.36 mol oxygen, 4.10 mol hydrogen, and 2.05 mol carb
Flura [38]

Answer:

C3H6O2

Explanation:

To find the empirical formula of the compound, we divide the amount in moles of each of the elements by the amount in mole of the element with the smallest number of mole. In this question, the element with the smallest number of moles is oxygen with 1.36 mole. Hence, we divide the number of moles of each element by this.

H = 4.10/1.36 = 3

O = 1.36/1.36 = 1

C = 2.05/1.36 = 1.5

We then multiply through by 2 to yield the compound with the empirical formula C3H6O2

7 0
2 years ago
Amino acids are the building blocks of proteins. The simplest amino acid is glycine (H2NCH2COOH). Draw a Lewis structure for gly
VashaNatasha [74]

Answer:

Explanation:

The lewis structure (indicating all the atoms and patterns provided as hint in the question) of glycine can be seen in the attachment below. While the chemical structure of glycine can be seen below

         H

          |

H₂N - C - C =O

          |      \

         H      OH

The structure (of glycine) above provides a "fair idea" of how the lewis structure will be.

3 0
2 years ago
Diborane, B2H6 a possible rocket propellant, can be made by using lithium hydride (LiH): 6 LiH+ 2 BCl2àB2H6+ 6 LiCl . If you mix
Genrish500 [490]

Answer :

(a) Limiting reactant = LiH

(b) The excess reactant = BCl_3

(c) The percent of excess reactant is, 50.87 %

(d) The percent yield of B_2H_6 or percent conversion of LiH to B_2H_6 is, 38.80 %

(e) The mass of LiCl produced is, 1066.42 lb

Explanation : Given,

Mass of LiH = 200 lb = 90718.5 g

conversion used : (1 lb = 453.592 g)

Mass of BCl_3 = 1000 lb = 453592 g

Molar mass of LiH = 7.95 g/mole

Molar mass of BCl_3 = 117.17 g/mole

Molar mass of B_2H_6 = 27.66 g/mole

Molar mass of LiCl = 42.39 g/mole

First we have to calculate the moles of LiH and BCl_3.

\text{Moles of }LiH=\frac{\text{Mass of }LiH}{\text{Molar mass of }LiH}=\frac{90718.5g}{7.95g/mole}=11411.13moles

\text{Moles of }BCl_3=\frac{\text{Mass of }BCl_3}{\text{Molar mass of }BCl_3}=\frac{453592g}{117.17g/mole}=3871.23moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

6LiH+2BCl_3\rightarrow B_2H_6+6LiCl

From the balanced reaction we conclude that

As, 6 moles of LiH react with 1 mole of BCl_3

So, 11411.13 moles of LiH react with \frac{11411.13}{6}=1901.855 moles of BCl_3

From this we conclude that, BCl_3 is an excess reagent because the given moles are greater than the required moles and LiH is a limiting reagent and it limits the formation of product.

Moles of remaining excess reactant = 3871.23 - 1901.855 = 1969.375 moles

Total excess reactant = 3871.23 moles

Now we have to determine the percent of excess reactant (BCl_3).

\% \text{ excess reactant}=\frac{\text{Moles of remaining excess reactant}}{\text{Moles of total excess reagent}}\times 100

\% \text{ excess reactant}=\frac{1969.375}{3871.23}\times 100=50.87\%

The percent of excess reactant is, 50.87 %

Now we have to calculate the moles of B_2H_6.

As, 6 moles of LiH react to give 1 mole of B_2H_6

So, 11411.13 moles of LiH react to give \frac{11411.13}{6}=1901.855 moles of B_2H_6

Now we have to calculate the mass of B_2H_6.

\text{Mass of }B_2H_6=\text{Moles of }B_2H_6\times \text{Molar mass of }B_2H_6

\text{Mass of }B_2H_6=(1901.855mole)\times (27.66g/mole)=52605.3093g

Now we have to calculate the percent yield of B_2H_6.

\%\text{ yield of }B_2H_6=\frac{\text{Actual yield of }B_2H_6}{\text{Theoretical yield of }B_2H_6}\times 100=\frac{20411.7g}{52605.3093g}\times 100=38.80\%

The percent yield of B_2H_6 or percent conversion of LiH to B_2H_6 is, 38.80 %

Now we have to calculate the moles of LiCl.

As, 6 moles of LiH react to give 6 mole of LiCl

So, 11411.13 moles of LiH react to give 11411.13 moles of LiCl

Now we have to calculate the mass of LiCl.

\text{Mass of }LiCl=\text{Moles of }LiCl\times \text{Molar mass of }LiCl

\text{Mass of }LiCl=(11411.13mole)\times (42.39g/mole)=483717.8007g=1066.42lb

The mass of LiCl produced is, 1066.42 lb

8 0
2 years ago
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