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Ivan
2 years ago
8

Describe one "Newton's third law pair" of forces involved in the following situations; in each case state the object that each f

orce acts on, the type of force and direction of force (a) you step on someone's toe (b) a car hits a brick wall and comes to rest (c) a car slows down by applying the brakes (d) you throw a ball upwards into the air
Physics
1 answer:
zalisa [80]2 years ago
8 0

Newton's third law pair states that:

"when an object A exerts a force on object B, object B exerts an equal and opposite force on object B"

Applied to this exercise:


(a) you step on someone's toe

The action-reaction pair in this situation is:

- The force of your feet on the other person toe (downward)

- The force the toe applied on your feet (upward)


(b) a car hits a brick wall and comes to rest

The action-reaction pair in this situation is:

- The force applied by the car on the wall (direction: towards the wall)

- The reaction force applied by the wall on the car (direction: towards the car)


(c) a car slows down by applying the brakes

An example of action-reaction pair in this situation is:

- The force of friction the tires exert on the road, that makes the car slow down

- The reaction force exerted by the road on the tires, which is also a force of friction


(d) you throw a ball upwards into the air

The action-reaction pair in this situation is:

- The force you apply on the ball when throwing it (direction: upward)

- The reaction force the ball exerts on your hand (direction: downward)




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Force due to radiation is given by

F=\dfrac{IA}{c}\\\Rightarrow F=\dfrac{\dfrac{P}{4\pi r^2}{\pi R^2}}{c}\\\Rightarrow F=\dfrac{PR^2}{4r^2c}

According to the question

F=mg\\\Rightarrow \dfrac{PR^2}{4r^2c}=\rho \dfrac{4}{3}\pi R^3g\\\Rightarrow P=\dfrac{16r^2\rho c\pi Rg}{3}\\\Rightarrow P=\dfrac{16\times 0.002\times 19000\times \pi\times 0.5^2\times 9.81\times 3\times 10^8}{3}\\\Rightarrow P=468449163762.0812\ W

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2 years ago
Is velocity ratio of a machine affected by applying oil on it?Explain with reason.​
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Methods to reduce friction

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