Answer:
The answer is: 51.8 g (86% of serving size)
Explanation:
In order to solve the problem, we have to first determine the number of moles there are in 11.0 g of sucrose. Sucrose has a molecular weight of 342 g (we calculate this from the molar mass of the elements : 12 x 12 g/mol C + 22 x 1 g/mol H + 11 x 16 g/mol O). So, we divide the mass (11.0 g) into the molecular weight of sucrose:
11.0 g sucrose x 1 mol/342 g sucrose= 0.032 mol
We have 0.032 mol of sucrose in a serving of 60 g. But we need less moles (0.0278 mol):
0.032 mol ------------ 60 g serving
0.0278 mol------------ x= 0.0278 mol x 60 g serving/0.032 mol
x= 51.8 g
So, lesser than 1 serving of 60 g must be eaten to consume 0.0278 mol os sucrose. Exactly, 51.8 g (which stands for a 86% of the serving size).
w/w percentage <span>
= mass of the pure compound /
total mass of the sample x 100%
70% HNO₃
contains by mass means every 100 g of sample has 70 g of HNO₃.</span><span>
The mass of solution = 103.8 g
Hence the mass of HNO₃ = 103.8 g x 70%</span><span>
= 103.8 g x (70 / 100)
<span>
= 72.66 g = 72.7 g.</span></span>
The graph is not given in the question, so, the required graph is attached below:
Answer:
According to the graph, the relationship between the density of the sugar solution and the concentration of the sugar solution is directly proportional to each other as they both are increasing exponentially.
The graph shows that, the density of sugar solution will increase with the increase in concentration of sugar in the solution.
The Structure of Glycine is attached below and each central atom is encircled with different colors.
Molecular Shape around Nitrogen Atom (Orange):
As shown, Nitrogen is making three single bonds with two hydrogen atoms and one carbon atom hence, it has three bonded pair electrons and a single lone pair of electron. Therefore, according to VSEPR theory it has a tetrahedral electronic geometry but due to repulsion created by lone pair of electrons its molecular geometry becomes Trigonal Pyramidal.
Molecular Shape around Carbon Atom (Green):
As shown, Carbon is making four single bonds with two hydrogen atoms and one nitrogen atom one with carbon atom of carbonyl group hence, it has four bonded pair electrons. Therefore, according to VSEPR theory it has Tetrahedral geometry.
Molecular Shape around Carbon Atom (Blue):
As shown, Carbon is making two single bonds with oxygen and carbon atoms and a double bond with oxygen. Hence, it has a Trigonal Planar geometry.
Molecular Shape around Oxygen Atom (Red):
As shown, Oxygen is making two single bonds with one carbon atoms and one hydrogen atom hence, it has two bonded pair electrons and two lone pair of electrons. Therefore, according to VSEPR theory it has a tetrahedral electronic geometry but due to repulsion created by lone pair of electrons its molecular geometry becomes Bent.