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Marat540 [252]
2 years ago
9

From the graph of Density vs. Concentration, created in Graph 1, what was the relationship between the concentration of the suga

r solution and the density of the sugar solution?

Chemistry
1 answer:
USPshnik [31]2 years ago
8 0

The graph is not given in the question, so, the required graph is attached below:

Answer:

According to the graph, the relationship between the density of the sugar solution and the concentration of the sugar solution is directly proportional to each other as they both are increasing exponentially.

The graph shows that, the density of sugar solution will increase with the increase in concentration of sugar in the solution.

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If you have 10.0 grams of citric acid with enough baking soda (nahco3 how many moles of carbon dioxide can you produce?
kap26 [50]
Easy stoichiometry conversion :)

So, for stoichiometry, we always start with our "given". In this case, it would be the 10.0 grams of NaHCO3. This unit always goes over 1.

So, our first step would look like this:

10.0
------
  1

Next, we need to cancel out grams to get to moles. To do this, we will do grams of citric acid on the BOTTOM of the next step, so it cancels out. This unit in grams will be the mass of NaHCO3, which is 84.007. Then, we will do our unit of moles on top. Since this is unknown, it will be 1.

So, our 2nd step would look like this:

1 mole CO2
-----------------
84.007g NaHCO3

When we put it together: our complete stoichiometry problem would look like this:

10.0g NaHCO3     1mol CO2
---------------------- x -------------------------
            1                  84.007g NaHCO3

Now to find our answer, all we need to do is:
Multiply the two top numbers together (which is 10.0)
Multiply the two bottom numbers together (Which is 84.007)

And then....

Divide the top answer by the bottom answer.

10.0/84.007 is 0.119

So, from 10.0 grams of citric acid, we have 0.119 moles of CO2.

Hope I could help!
6 0
2 years ago
Read 2 more answers
An electrically neutral atom of gallium has 31 electrons and 39 neutrons. What is the mass number for an atom of gallium?. A. 31
hammer [34]
If the atom is neutral (meaning, not charged) the number of electron is equal to the number of protons. The mass number of an atom is the sum of the number of proton and the number of neutrons. From the given above, the mass number of gallium is 31 + 39. The answer is letter D. 70.
4 0
2 years ago
Read 2 more answers
How many grams of fluorine are contained in 8 molecules of boron trifluoride?
Lelu [443]
<h3>Answer:</h3>

             7.57 × 10⁻²² g of F

<h3>Solution:</h3>

Data Given:

                 Number of Molecules  =  8

                 M.Mass of BF₃ =  67.82 g.mol⁻¹

                 Mass of Fluorine atoms  =  ?

Step 1: Calculate Moles of BF₃

           Moles  =  Number of Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

Putting value,

            Moles  =   8 Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

            Moles  =  1.33 × 10⁻²³ mol

Step 2: Calculate Mass of BF₃:

                   Moles  =  Mass ÷ M.Mass

Solving for Mass,

                   Mass  =  Moles × M.Mass

Putting values,

                   Mass  =  1.33 × 10⁻²³ mol × 67.82 g.mol⁻¹

                   Mass  =  9.0 × 10⁻²² g

Step 3: Calculate Mass of Fluorine Atoms:

As,

                         67.82 g BF₃ contains  =  57 g of F

So,

                    9.0 × 10⁻²² g will contain  =  X g of F

Solving for X,

                       X =  (9.0 × 10⁻²² g × 57 g) ÷ 67.82 g

                        X  =  7.57 × 10⁻²² g of F

4 0
2 years ago
Read 2 more answers
Which of the following concerning electrolytes and the solubility rules is/are true? 1. The solubility rules apply only to ionic
Mkey [24]

Answer:

1. is true  

Explanation:

The solubility rules apply only to salts, which are ionic compounds.

2. is false. A strong electrolyte is a salt that dissociates completely in solution. Not all salts dissociate completely. For example, a 0.36 mol·L⁻¹ solution dissociates as:

K₂SO₄ ⟶ K⁺   + KSO₄⁻ (30 %) + SO₄²⁻

Thus, K₂SO₄ does not dissociate completely into K⁺ and SO₄²⁻ ions.

3. is false. The solubility rules apply only to aqueous solutions.

7 0
2 years ago
As a part o a clinical study, a pharmacist is asked to prepare a modi ication o a standard 22 g package o a 2% mupirocin ointmen
son4ous [18]

Answer:

240 mg

Explanation:

In a dilution, the total quantity of the solute remains equal, so the concentration multiplied by the volume, or mass, of it, must be constant. In this case, the concentration is measured by the mass (w/w), so:

C1M1 = C2M2

Where C is the concentration, M is the mass, 1 is the concentrated solution, and 2 the diluted. The powder mupirocin has 100% of concentration, and the diluted solution will be mass equal to 22 g plus the mass added, so:

100%*M1 = 3%*(22 + M1)

100M1 = 66 + 3M1

97M1 = 66

M1 = 0.6804 g

But the ointment already has 2% of mupirocin, which is in mass:

0.02* 22 = 0.44 g

So, the mass needed to be added is 0.6804 - 0.44 = 0.24 g = 240 mg

4 0
2 years ago
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