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hjlf
2 years ago
8

By constructing basic electric circuits, you will be able to measure current flow. With Ohm’s law in mind, what broad question a

re you answering by doing this experiment?
Physics
2 answers:
NemiM [27]2 years ago
8 0

Answer:

Sample Response: How do changes in voltage or resistance affect current in an electric circuit?

Explanation:

andrezito [222]2 years ago
5 0

Broad questions that we can answer by doing this experiment are <em><u>the effects of electric current</u></em>

<h3>Further explanation</h3>

Electric current is the amount of electric charge that flows each unit of time

Electric current occurs due to the movement of electrons due to the difference in potential or voltage (from high potential to low potential) between two points

Electrons will flow through the conducting wire that functions as a conductor

Ohm's Law states that

<em>The potential difference is proportional to the electric current as long as the resistance is constant</em>

\displaystyle I=\frac{V}{R}\\\\V=I\times R

A simple electrical circuit consists of a voltage source (battery) and a lamp

Ampermeters to measure the strength of the current, must be installed in series with the load to be measured

By changing the voltage source, with constant resistance from a conductor, different current measurements will be obtained. The greater the voltage, the greater the resulting current.

<h3>Learn more</h3>

electrons flow through the device

brainly.com/question/4438943

Keywords : basic electric circuits, Ohm’s law, experiment

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A mercury atom in the ground state absorbs 20.00 electronvolts of energy and is ionized by losing an electron. How much kinetic
sukhopar [10]
We are given a mercury atom in the ground state which absorbs 20 eV of energy. It is then ionized by losing an electron. We need to calculate the kinetic energy that the electron has after ionization.

The initial energy is 20 eV = 20 J/C
The electron charge is = 1.60217662 × 10-19<span> coulombs

To determine the kinetic energy, we can use this equation:

KE = 20 Joules / Coulombs * </span>1.60217662 × 10-19<span> coulombs 
KE = 1.25x10^20 Joules 

Therefore, the amount of kinetic energy that the electron has after ionization is </span>1.25x10^20 Joules or 1.25x10^17 kJ. <span />
8 0
2 years ago
A 4.5-m-long wooden board with a 24-kg mass is supported in two places. One support is directly under the center of the board, a
JulijaS [17]

All the weight of the wooden board is bear by the support located at the centre of the rod, and the other support which is located at the end, will have no reaction force, or 0 reaction force.

Therefore the reaction at the centre support is equal to the weight of the board, while the support at the end has 0 reaction force.

8 0
2 years ago
Read 2 more answers
Two small aluminum spheres, each of mass 0.0250 kilograms, areseparated by 80.0 centimeters.
sineoko [7]

Answer:

Total number of electrons

N = 7.25 \times 10^{24}

electrons removed from each sphere

N = 5.27 \times 10^{15}

Fraction of electrons transferred is given as

f = 7.27 \times 10^{-10}

Explanation:

As we know that moles is defined as

n =\frac{mass}{molar mass}

n = \frac{0.0250}{0.026982}

n = 0.93

so number of atoms of Al in each sphere is given as

N = 0.93(6.02 \times 10^{23})

N = 5.58 \times 10^{23}

Now number of electrons in each atom is given as

atomic number = number of electrons in each atom = 13

total number of electrons in each sphere is

N = 13 \times (5.58 \times 10^{23})

N = 7.25 \times 10^{24}

Also we know that force of attraction between them is given as

F= \frac{kq_1q_2}{r^2}

1.00 \times 10^4 = \frac{(9\times 10^9)q^2}{0.80^2}

q = 8.4 \times 10^{-4} C

now we have

q = Ne

8.4 \times 10^{-4} = N(1.6 \times 10^{-19}

N = \frac{(8.4 \times 10^{-4})}{1.6 \times 10^{-19}}

N = 5.27 \times 10^{15}

Fraction of electrons transferred is given as

f = \frac{5.27 \times 10^{15}}{7.25 \times 10^{24}}

f = 7.27 \times 10^{-10}

6 0
2 years ago
Un tren emplea cierto tiempo en recorrer 240 km. Si la velocidad hubiera sido 20 km por hora mas que la que llevaba hubiera tard
podryga [215]

Answer:

A train takes some time to travel 240 km. If the speed had been 20 km per hour more than the one it was carrying, it would have taken 2 hours less to travel this distance. In what time did he cover the 240 km

Explanation:

Given that,

A train travelled a distance of 240km

Let the initial speed be

S_1 = x km/hr

Let assume the time spent on the first journey is

t_1 = a

Now if he increase the speed to

S_2 = (x + 20) km/hr

Then, he would have take 2hrs less time

Then, time t_2 = a - 2

The common data fore the two journey is the distance

Speed = distance / time

For the first stage

S_1 = d / t_1

d = S_1 × a

d = x × a

240 = x•a

x = 240 / a Equation 1

For stage two

d = S_2 × t_2

d = (x+20) × (a - 2)

240 = (x+20) × (a - 2). Equation 2

Substitute equation 1 into 2

240 = (240/a + 20) × (a -2)

240 = 240 - 480/a + 20a - 40

240 - 240 + 40 = - 480/a + 20a

240 - 240 + 40 = (-480 + 20a²) / a

40 = (-480 + 20a²) / a

40a = -480 + 20a²

20a² - 40a -480 = 0

Divided through by 20

a² - 2a - 24 = 0

a² + 4a - 6a - 24 = 0

a(a+4) -6(a+4) = 0

(a-6)(a+4) = 0

(a-6) = 0 or (a+4) = 0

So, a = 6 or a = -4

The time cannot be negative, then, the time is a = 6hours

So, t_1 = a = 6hours,

So, the time used in the first journey is 6hours

So, in the second journey the time use is 2hours less than the first journey

Then, t_2 = 6 - 2 = 4 hours

t_1 = 6 hours

t_2 = 4 hours

Spanish

Un tren recorrió una distancia de 240 km.

Deje que la velocidad inicial sea

S_1 = x km / h

Supongamos que el tiempo dedicado al primer viaje es

t_1 = a

Ahora si aumenta la velocidad a

S_2 = (x + 20) km / h

Entonces, habría tomado 2 horas menos de tiempo

Entonces, el tiempo t_2 = a - 2

Los datos comunes para los dos viajes son la distancia.

Velocidad = distancia / tiempo

Para la primera etapa

S_1 = d / t_1

d = S_1 × a

d = x × a

240 = x • a

x = 240 / a Ecuación 1

Para la etapa dos

d = S_2 × t_2

d = (x + 20) × (a - 2)

240 = (x + 20) × (a - 2). Ecuación 2

Sustituye la ecuación 1 en 2

240 = (240 / a + 20) × (a -2)

240 = 240 - 480 / a + 20a - 40

240 - 240 + 40 = - 480 / a + 20a

240 - 240 + 40 = (-480 + 20a²) / a

40 = (-480 + 20a²) / a

40a = -480 + 20a²

20a² - 40a -480 = 0

Dividido entre 20

a² - 2a - 24 = 0

a² + 4a - 6a - 24 = 0

a (a + 4) -6 (a + 4) = 0

(a-6) (a + 4) = 0

(a-6) = 0 o (a + 4) = 0

Entonces, a = 6 o a = -4

El tiempo no puede ser negativo, entonces, el tiempo es a = 6 horas

Entonces, t_1 = a = 6 horas,

Entonces, el tiempo utilizado en el primer viaje es de 6 horas

Entonces, en el segundo viaje, el uso del tiempo es 2 horas menos que el primer viaje

Entonces, t_2 = 6 - 2 = 4 horas

t_1 = 6 horas

t_2 = 4 horas

5 0
2 years ago
A certain signal molecule S in heart tissue is degraded by two different biochemical pathways: when only Path 1 is active, the h
Misha Larkins [42]

Answer:

Half life of S = 3.76secs

Explanation:

The concept of half life in radioactivity is applied. Half life is the time taken for a radioactive material to decay to half of its initial size.

For part 1 - How much signal will be degraded in 1secs = 1/3.9 = 0.2564

for part 2 - How much signal will be degraded in 1secs = 1/104 = 0.009615

Simply say = 1/3.9 + 1/104 = 0.266015

So both part 1 and part 2 took 1/0.266015 = 3.76secs is the half life of S when both pathways are active

6 0
2 years ago
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