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hjlf
2 years ago
8

By constructing basic electric circuits, you will be able to measure current flow. With Ohm’s law in mind, what broad question a

re you answering by doing this experiment?
Physics
2 answers:
NemiM [27]2 years ago
8 0

Answer:

Sample Response: How do changes in voltage or resistance affect current in an electric circuit?

Explanation:

andrezito [222]2 years ago
5 0

Broad questions that we can answer by doing this experiment are <em><u>the effects of electric current</u></em>

<h3>Further explanation</h3>

Electric current is the amount of electric charge that flows each unit of time

Electric current occurs due to the movement of electrons due to the difference in potential or voltage (from high potential to low potential) between two points

Electrons will flow through the conducting wire that functions as a conductor

Ohm's Law states that

<em>The potential difference is proportional to the electric current as long as the resistance is constant</em>

\displaystyle I=\frac{V}{R}\\\\V=I\times R

A simple electrical circuit consists of a voltage source (battery) and a lamp

Ampermeters to measure the strength of the current, must be installed in series with the load to be measured

By changing the voltage source, with constant resistance from a conductor, different current measurements will be obtained. The greater the voltage, the greater the resulting current.

<h3>Learn more</h3>

electrons flow through the device

brainly.com/question/4438943

Keywords : basic electric circuits, Ohm’s law, experiment

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alisha [4.7K]

Answer:

Check Explanation

Explanation:

Let the speed of the drone relative to earth be u = ?

Let the speed of the drone relative to the starship be u' = 0.5c

Let the speed of the starship relative to earth be v = 0.8c

In the theory of relativity,

The 3 speeds are related thus

u = (u' + v)/[1 + (u'v/c²)]

u = (0.5c + 0.8c)[1 + ((0.8c × 0.5c)/c²)]

u = 1.3c/[1 + (0.4c²/c²)]

u = 1.3c/1.4 = 0.9286 c = 0.93 c = 93% c

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2 years ago
Light from a lamp is shining on a surface. how can you increase the intensity of the light on the surface?
vlada-n [284]
The intensity of a light in a surface follows the inverse square law formula which can be mathematically expressed as,
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where I is intensity, d is distance, and k is the proportionality constant. For us to increase the intensity, we should lower the distance from the source to the surface. 
4 0
2 years ago
A Porsche 944 Turbo has a rated engine power of 217hp . 30% of the power is lost in the drive train, and 70% reaches the wheels.
scZoUnD [109]

Explanation:

(a)  It is given that two-third of weight is over the drive wheels. So, mathematically, w = \frac{2}{3}mg.

Hence, maximum force is expressed as follows.

                F_{max} = \mu_{s} \times w

           m \times a_{max} = \mu_{s} (\frac{2}{3} mg)

Hence, the maximum acceleration is calculated as follows.

             a_{max} = \frac{2}{3} \mu_{s} \times g

                          = \frac{2}{3} \times 1.00 \times 9.8 m/s^{2}

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Hence, the maximum acceleration of the Porsche on a concrete surface where μs = 1 is 6.53 m/s^{2}.

(b)  Since, 30% of the power is lost in the drive train. So, the new power is 70% of P_{max}.

That is,   new power = 0.7 \times P_{max}

Now, the expression for power in terms of force and velocity is as follows.

                      P = F_{max} \nu

              0.7 P_{max} = ma_{max} \nu

Therefore, speed of the Porsche at maximum power output is as follows.

            \nu = 0.7 \times \frac{P_{max}}{ma_{max}}

                      = 0.7 \times \frac{217 hp \times \frac{746 W}{1 hp}}{1500 kg \times 6.53 m/s^{2}}

                      = 11.568 m/s

                      = 11.57 m/s

Therefore, speed of the Porsche at maximum power output is 11.57 m/s.

(c)   The time taken will be calculated as follows.

             time = \frac{\text{velocity}}{\text{acceleration}}

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Therefore, the Porsche takes 1.77 sec until it reaches the maximum power output.

6 0
2 years ago
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Answer:

Explanation:

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Which of the following statements is FALSE?
Levart [38]

A thrust fault is a reverse fault with an extremely high dip (close to 90°). This is the false statement.

Answer: Option D

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There is dip-slip fault which has its movement along the vertical fault plane while the strike slip fault will be in horizontal direction. Similarly, an oblique fault will be acting in both vertical and the horizontal direction. So, the fourth statement related to thrust fault is false as in reverse fault or thrust fault the dip will be shallow and not high.

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2 years ago
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