Answer:
Total energy saving will be 0.8 KWH
Explanation:
We have given there are 50 long light bulbs of power 100 W so total power of 50 bulb = 100×50 = 5000 W = 5 KW
30 bulbs are of power 60 W
So total power of 30 bulbs = 30×60 = 1800 W = 1.8 KW
Total power of 80 bulbs = 1.8+5 = 6.8 KW
Total time = 3 hour
We know that energy
Now power of each CFL bulb = 25 W
So power of 80 bulbs = 80×25 = 2000 W = 2 KW
Energy of 80 bulbs = 2×3 = 6 KWH
So total energy saving = 6.8-6 = 0.8 KWH
(a) The diffraction decreases
The formula for the diffraction pattern from a single slit is given by:
where
is the angle corresponding to nth-minimum in the diffraction pattern, measured from the centre of the pattern
n is the order of the minimum
is the wavelength
a is the width of the opening
As we see from the formula, the longer the wavelength, the larger the diffraction pattern (because increases). In this problem, since the wavelength of the signal has been decreased from 54 cm to 13 mm, the diffraction of the signal has decreased.
(b)
The angular spread of the central diffraction maximum is equal to twice the distance between the centre of the pattern and the first minimum, with n=1. Therefore:
in this case we have
is the wavelength
is the width of the opening
Solving the equation, we find
So the angular spread of the central diffraction maximum is twice this angle:
(c)
Here we can apply the same formula used before, but this time the wavelength of the signal is
so the angle corresponding to the first minimum is
So the angular spread of the central diffraction maximum is twice this angle:
Answer:
A: 4 times as much
B: 200 N/m
C: 5000 N
D: 84,8 J
Explanation:
A.
In the first question, we have to caculate the constant of the spring with this equation:
Getting the k:
Then we can calculate how much the spring stretch whith the another mass of 0,2kg:
The energy of a spring:
For the first case:
For the second case:
If you take the relation E2/E1 = 4.
B.
We have the next facts:
x=0,005 m
E = 0,0025 J
Using the energy equation for a spring:
⇒
C.
The potential energy of the diver will be equal to the kinetic energy in the moment befover hitting the watter.
Watch out the units in this case, the 500 N reffer to the weighs of the diver almost relative to the earth, thats equal to m*g.
D.
The work is equal to the force acting in the direction of the motion. so we have to do the diference beetwen angles to obtain the effective angle where the force is acting: 47-15=32 degree.
The force acting in the direction of the ramp will be the projection of the force in the ramp, equal to F*cos(32). The work will be:
W=F*d=F*cos(32)*d=10N*cos(32)*10m=84,8J