Answer:
Well, I don't think I can remember EVERY skill I was taught through the years but in Kindergarten we used Number Sense so we could accurately... also there's estimation and of course PEMDAS. I've also learned how to round up so that the solution is at least around those numbers if the skill is to be applied.
Step-by-step explanation:
I'm not sure if this'll help but go ahead and have it... just try and change it a bit so they don't get ya for plagirism
The correct question is
<span>Javier is making a cake for a party. The recipe calls for 2 3/4 cups of flour, but he wants to triple the recipe. He guessed and put in 7 cups of flour. How many more cups of flour should he have used?
we know that
2 3/4 cups of flour------> (2*4+3)/4----> 11/4 cups
if he </span>wants to triple the recipe------> 3*(11/4)----> 33/4 ----> 8 1/4 cups required
8 1/4-7=1 1/4 cups
the answer is
1 1/4 cups
Let us say that the intersection point of lines
AB and CD is called point E. The lines AB and CD are perpendicular to each
other which also means that the triangle CEB is a right triangle.
Where the line CB is the radius of the circle
while the side lengths are half of the whole line segment:
EB = 0.5 AB = 0.5 (8 ft) = 4 ft
CE = 0.5 CD = 0.5 (6 ft) = 3 ft
Now using the hypotenuse formula since the
triangle is right triangle, we can find for the radius or line CB:
CB^2 = EB^2 + CE^2
CB^2 = (4 ft)^2 + (3 ft)^2
CB^2 = 16 ft^2 + 9 ft^2
CB^2 = 25 ft^2
<span>CB = 5 ft = radius</span>
7 MPH because 2 1/3
in 20 minutes. So you multiply 20 by 3 you get 60. Then you multiply 2 by 3 you get 6. Then you multiply 1/3 x 3 and you get 1. 6=1=7 Hope This Helps
To find the magnitude of the resultant vector, the formula is written as:
R² = x² + y²,
where
x and y are the perpendicular vectors along x and y axes, respectively.
So, any pair of x and y must satisfy the given equation. There are a lot os possibilities. Let's say, if x = 12, then,
20² = 12² + y²
y = 16
One answer would be a horizontal x vector equal to 12 m, and a vertical y vector equal to 16 m.
