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aleksandr82 [10.1K]
2 years ago
5

Sodium oxide (Na2O) crystallizes in a structure in which the O2– ions are in a face - centered cubic lattice and the Na+ ions ar

e in tetrahedral holes. What is the number of Na+ ions in the unit cell?
A)2
B)4
C)6
D)8
E)none of these
Chemistry
1 answer:
melisa1 [442]2 years ago
3 0

We have to know the number of Na⁺ ions in the unit cell.

The number of Na⁺ ions in the unit cell is (D) 8.

Sodium oxide (Na2O) crystallizes in a structure in which the O2– ions are in a face - centered cubic lattice and the Na+ ions are in tetrahedral holes.

O²⁻ ions are in a face centred cubic lattice, so the number of O²⁻ ions per unit cell is equal to 4. The number of  tetrahedral hole= 2 X 4=8. Na+ ions are present in tetrahedral holes, which indicates there are 8 number of Na+ ions in the unit cell.


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Mrs. Jacobson is pushing a fridge to the right with a force of 100 N. The force pushing it
alex41 [277]

Answer:

A

Explanation:

Let's illustrate this; see the attachment.

We see that Mrs. Jacobson is pushing to the right with a force of 100 N and there is another opposite force pushing with a force of 15 N. Since these are in opposite directions, we can say that the force opposite to Mrs. Jacobson is pushing the fridge -15 N to the right (instead of 15 N to the left).

The net force would then be:

100 N + (-15 N) = 85 N to the right

The answer is A.

8 0
2 years ago
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Match each set of quantum numbers to the correct subshell description by typing in the correct number. 1: n = 2, l = 0 2p: 2: n
Reil [10]

Answer:

4

2

1

5

3

Explanation:

4 0
2 years ago
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Use the conversion factor 1amu=6.66054 x 10^-24 to answer the following questions.. . a) 1.674 x 10^-24 g of neutrons is how man
Wewaii [24]
A.) The conversion factor is 1 amu = 1.66054 ^{-24}g

To know how many amu in 1.674x10^{-24}g grams of neutrons:
1.674x10^{-24}g ( \frac{x (amu) }{ 1.66054x10^{-24} g)}

=1.00811 amu

b.) The mass in grams of one lithium ion which has an atomic weight of 6.94 amu.

6.94 amu (\frac{6.66054 ^{-24} g}{1 amu}) = 4.62241x10 ^{23} g

c.) How many amu in 6.492x10^-23g potassium?

6.492x10^{-23}g ( \frac{x (amu) }{ 1.66054x10^{-24}g }) = 39.0957 amu


6 0
2 years ago
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A birthday balloon had a volume of 14.1 L when the gas inside was at a temperature of 13.9 °C. Assuming no gas escapes, what is
bixtya [17]

Answer:

14.5L

Explanation:

The following data were obtained from the question:

V1 = 14.1L

T1 = 13.9°C = 13.9 + 273 = 286.9K

T2 = 22°C = 22 + 273 = 295K

V2 =?

Using charles' law: V1/T1 = V2 /T2, we can obtain the new volume as follows:

14.1/286.9 = V2 /295

Cross multiply to express in linear form

286.9 x V2 = 14.1 x 295

Divide both side by 286.9

V2 = (14.1 x 295) / 286.9

V2 = 14.5L

Therefore, the new volume = 14.5L

8 0
3 years ago
How many electrons are transferred in the given redox reaction?<br><br> Zn+2AgNO3⟶2Ag+Zn(NO3)2
Vsevolod [243]

Answer:

2 electrons are transfered in this reaction.

Explanation:

Oxidation is a reaction where an atom, ion, or molecule loses electrons, while reduction corresponds to the electron gain of an atom, ion, or molecule.

In an oxidation-reduction reaction two simultaneous processes take place, oxidation and reduction.

So, oxidation-reduction (redox) reactions involve the transfer of electrons between chemical species. They are also called electron transfer reactions since the particle that is exchanged is the electron.

In this case:

Zn(s) ⇒ Zn²⁺(aq) + 2 e⁻

2 Ag⁺  (aq) + 2 e⁻ ⇒ 2 Ag(s)

So, zinc metal loses two electrons to form the zinc(II) ions, while the two silver ions each gain one  electron to form two silver metal atoms.

Then, Zn is a reducing agent (The reducing agent is the one that provides the electrons, oxidizing itself), AgNO3 is an oxidizing agent (The oxidizing agent is the one that traps the electrons, reducing itself).

Finally, you can see that <u><em>2 electrons are transfered in this reaction.</em></u>

7 0
2 years ago
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