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ale4655 [162]
2 years ago
13

The maximum acceptable concentration of fluoride in tap water is 1.5mg/L. Express this concentration in ppm. Then figure what vo

lume of tap water contains 1.0 g of fluroide
Chemistry
1 answer:
MrMuchimi2 years ago
3 0

Given that the maximum acceptable concentration of fluoride in tap water = 1.5 mg/L.

1 mg/L is equivalent to 1 parts per million(ppm).

Converting 1.5 mg/L to ppm:

1.5\frac{mg}{L} *\frac{1 ppm}{1\frac{mg}{L} } =1.5 ppm

So the maximum acceptable concentration of fluoride in tap water in ppm is 1.5 ppm.

Finding out the volume of tap water that would contain 1.0 g fluoride:

Converting 1.0 g fluoride to mg:1.0g*\frac{1000mg}{1g}=1000mg

Taking the concentration of fluoride in tap water to be 1.5 mg/L,

Volume of tap water that contains 1000 mg fluoride

                              =1000mg*\frac{1mL}{1.5mg}=666.67 mL

Rounding the volume to three significant figures, 667 mL of tap water.



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Leto [7]

Answer : The final temperature of the copper is, 87.29^oC

Solution :

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\Delta T=\text{Change in temperature} 

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Now put all the given values in the above formula, we get the final temperature of copper.

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andrew11 [14]

Explanation:

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At pH = 6, the concentration of H^+ ions is 1\times 10^{-6} M.

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maksim [4K]
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Now we solve for x

X^2= 6.3x10-9
x= square root(6.3x10-9)
x= 7.94x10-5
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