It is scandium or titanium iron chroniclemium vanadium manganese
Answer:
C The water had adequate nitrogen and phosphorus, so it is likely iron limited.
Explanation:
Phytoplankton are single- cell organisms that live in oceans.
They require nitrogen, phosphorus and trace amount of iron to survive.
From the scientist's results after testing the water for nitrogen and phosphorus,there are reasonable amount of these elements.
Therefore insufficient iron in the water is the reason why he could find plenty phytoplankton in the ocean.
Answer:
-) 3-bromoprop-1-ene
-) 2-bromoprop-1-ene
-) 1-bromoprop-1-ene
-) bromocyclopropane
Explanation:
In this question, we can start with the <u>I.D.H</u> (<em>hydrogen deficiency index</em>):
In the formula we have 3 carbons, 5 hydrogens, and 1 Br, so:
We have an I.D.H value of one. This indicates that we can have a cyclic structure or a double bond.
We can start with a linear structure with 3 carbon with a double bond in the first carbon and the Br atom also in the first carbon (<u>1-bromoprop-1-ene</u>). In the second structure, we can move the Br atom to the second carbon (<u>2-bromoprop-1-ene</u>), in the third structure we can move the Br to carbon 3 (<u>3-bromoprop-1-ene</u>). Finally, we can have a cyclic structure with a Br atom (<u>bromocyclopropane</u>).
See figure 1
I hope it helps!
Answer:
En toda la población del mundo hay <u>0.0797 moles de células</u>
Explanation:
1.0 mol of cells = 6.022 * 10∧23 cells
X mol of cells = 6.0 * 10∧12 cells
- X is cleared to find out how many moles of cells are in a human body:
- X = 6.0 * 10∧12 cells / 6.022 * 10∧23 cells
- X = 9,963 * 10∧-12 moles of cells per person
In the world there are 8 * 10∧9 people, how many moles in total will there be?
8 * 10∧9 people * 9,963 * 10∧-12 moles of cells per person =
<u>0.0797 moles of molecules in the entire population of the earth.</u>
The hydroxide concentration is written as [OH-]. A useful equation is that pH + pOH = 14. Since the pH is 4, the pOH must be 10. To get [OH-], again take the neg. anti-log of both sides: - anti log (pOH-) = - antilog(10) ---> [OH-]=1 x 10^-10 M or 1 x 10^-10 moles [OH-] per liter solution (in this case, lake).
The hydroxide ion concentration describe in question 3 is 10-10 M
