94.20 g/3.16722 mL = 29.74 g/mL
The ratio of mass to volume is equal to the substance's density. Thus, 29.74 g/mL is the density of whatever substance it may be. Density does not change for incompressible matter like solid and some liquids. Although, it may be temperature dependent.
Answer:
a.)
To warm the liquid from 35°C to 78°C:
(2.3 J/g-K) x (42.0 g) x (78 - 35) = 4154 J
To vaporize the liquid at 78°C:
(38.56 kJ/mol) x (42.0 g C2H5OH / 46.06867 g C2H5OH/mol) = 35.154 kJ
Total:
4.154 kJ + 35.154 kJ = 39.3 kJ
b.)
To warm the solid from -155°C to -114°C:
(0.97 J/g-K) x (42.0 g) x (-114°C - (-155°C)) = 1670 J
To melt the solid at -114°C:
(5.02 kJ/mol) x (42.0 g C2H5OH / 46.06867 g C2H5OH/mol) = 4.5766 kJ
To warm the liquid from -114°C to 78°C:
(2.3 J/g-K) x (42.0 g) x (78 - (-114)) = 18547 J
To vaporize the liquid at 78°C:
35.154 kJ (as in part a.)
Total:
1.670 kJ + 4.5766 kJ + 18.547 kJ + 35.154 kJ = 59.9 kJ
Explanation:
Let's assume that both He and N₂ have ideal gas behavior.<span>
Then we can use ideal gas law,
PV = nRT
Where, P is the pressure of gas, V is the volume,
n is moles of gas, R is universal gas constant and T is the temperature in
Kelvin.
<span>The </span>P <span>and </span>V <span>are </span>same<span> for the
both gases.</span>
R is a
constant.
The only variables are n and T.
<span>Let's say temperature of </span>He<span> <span>is </span></span>T</span>₁<span> <span>and temperature of </span></span>N₂<span> <span>is </span></span>T₂.<span>
n = m/M<span> where n is
moles, m is mass and M is molar mass.</span>
Molar mass of He is 4 g/mol and molar mass of N₂ is 28 g/mol</span><span>
<span>Since mass (m) of both gases are same,</span>
moles of He = m/4
moles of N₂ = m/28</span><span>
Let's apply the ideal gas equation for both gases.
For He gas,
PV = (m/4)RT₁ </span>(1)<span>
For N</span>₂ gas,<span>
PV = (m/28)RT₂<span> </span></span> (2)<span>
(1) = (2)
</span><span>(m/4)RT₁ =
(m/28)RT₂</span> <span>
T₁/4
= T₂/28</span><span>
T₁ = T₂/7</span><span>
<span> </span>7T</span>₁ = T₂<span>
Hence, the
temperature of N</span>₂<span> gas is higher by 7
times than the temperature of He gas.</span>
Answer:
78.15 g
Explanation:
Number of moles of C₇H₆O₃ that reacted = mass/molar mass = 57.6g/126 gmol-1
Number of moles of C₇H₆O₃ = 0.457 moles of C₇H₆O₃
From the reaction equation;
1 mole of C₇H₆O₃ yields one mole of aspirin
0.457 moles of C₇H₆O₃ yields C₇H₆O₃ of aspirin
Hence theoretical yield of aspirin = 0.457 moles × 180 gmol-1 = 82.26g of aspirin
% yield = actual yield/theoretical yield ×100
Actual yield= % yield × theoretical yield/100
Actual yield = 95.0 × 82.26/100
Actual yield = 78.15 g
It changes the boiling point of the water, and it changes the freezing point of the water
