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anygoal [31]
2 years ago
6

If 29.4 mL of ethanol is dissolved in water to make 359 mL of solution, what is the concentration expressed in volume/volume % o

f the solute?
Chemistry
1 answer:
Sveta_85 [38]2 years ago
6 0

Answer: 8.2\%

Explanation:- Volume percentage is the ratio of volume of solute to the volume of solution defined in terms of percentage.

{\text {volume percentage}}=\frac{\text {volume of solute}}{\text {volume of solution}}\times 100\%

Given: volume of solute = 29.4 ml

Volume of solution= 359 ml

{\text {volume percentage}=\frac{29.4}{359}\times 100\%=8.2\%


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Elanso [62]

Answer:

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Alcohol-related diseases frequently cause low Mg+ levels.

- Mg+ deficiencies must be treated before potassium (K+) deficiencies.

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3 0
2 years ago
How many liters of a 0.225 M solution of KI are needed to contain 0.935 moles of KI?
Katyanochek1 [597]

Answer:

4.16L

Explanation:

From the question given, we obtained the following data:

Molarity = 0.225 M

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Volume = mole /Molarity

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Volume = 4.16L

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6 0
2 years ago
A sample of an alloy of aluminum contains 0.0898 mol Al and 0.0381 mol Mg. What are the mass percentages of Al and Mg in the all
blondinia [14]

Answer:

Al 72.61%

Mg 27.39%

Explanation:

To obtain the mass percentages, we need to place the individual masses over the total mass and multiply by 100%.

If we observe clearly, we can see that the parameters given are the moles. We need to convert the moles to mass.

To do this ,we need to multiply the moles by the atomic masses. The atomic mass of aluminum is 27 while that of magnesium is 24.

Now, the mass of aluminum is thus = 27 * 0.0898 = 2.4246g

The mass of magnesium is 0.0381 * 24 = 0.9144g

We can now calculate the mass percentage.

The total mass is 0.9144 + 2.4246 = 3.339g

% mass of Al = 2.4246/3.339 * 100 = 72.61%

% mass of Mg = 0.9144/3.39 * 100 = 27.39%

7 0
2 years ago
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masha68 [24]
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5 0
2 years ago
15. Using the information below, calculate ΔHf° for PbO(s)
Svet_ta [14]
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So, the best answer is A.
5 0
2 years ago
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