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aleksley [76]
2 years ago
9

If the reaction shown below is exothermic, the energy level of the reactants is ________. h2 + o2 → 2h2o

Chemistry
1 answer:
never [62]2 years ago
5 0

An exothermic reaction is one which is accompanied by the release of heat energy.

In the given situation, hydrogen and oxygen combine to form water along with the generation of heat.

2H2 + O2 → 2H2O + heat

Based on the law of conservation of energy: 'energy can be neither created nor destroyed". This implies that whatever energy is released must have been present in the reactants. Therefore, the reactants must be in a higher energy level than products.

If the reaction shown below is exothermic, the energy level of the reactants is higher than products.


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A sample of fluorine gas is confined in a 5.0-L container at 0.432 atm and 37 °C. How many moles of gas are in this sample?
Ahat [919]

Answer:

About 0.08486 moles

Explanation:

PV=nRT, when P is the pressure in atmospheres, V is the volume in liters, n is the number of moles, R is the universal gas constant, and T is the temperature in Kelvin.

0.432 \cdot 5= n \cdot 0.0821 \cdot 310

n\approx 0.08486 moles

Hope this helps!

7 0
2 years ago
The complex ion, [ni(nh3)6] 2+, has a maximum absorption near 580 nm. calculate the crystal field splitting energy (in kj/mol) f
Wewaii [24]
In given data:
maximum absorption wavelength λ = 580 nm = 580 x 10⁻⁹ m
write the equation to find the crystal field splitting energy:
E = hC / λ 
Here, E is the crystal field splitting energy, h = 6.63 x 10⁻³⁴ J.sec is Planck's constant and C = 3 x 10⁸ m/sec is speed of light. 
substitute in the equation above:
E = (6.64 x 10⁻³⁴ x 3 x 10⁸) / (580 x 10⁻⁹) = 3.43 x 10⁻¹⁹J
This crystal field splitting energy is for 1 ion.
Number of atoms in one mole, NA = 6.023 x 10²³ 
to calculate the crystal field splitting energy for one mole:
E(total) = E x NA
             = (3.43 x 10⁻¹⁹) x (6.023 x 10²³) = 206 kJ/ mole



 
5 0
2 years ago
Given that the density of TlCl(s) is 7.00 g/cm3 and that the length of an edge of a unit cell is 385 pm, determine how many form
ryzh [129]
Here's my best guess
the volume of the unit cell is (385*10^-12)^3=5.7066*10^-29 m^3
multiply by density to get mass mass = (7 g/cm^3)*(100^3 cm^3 / 1^3 m^3) * 5.7066*10^-29 m^3= 3.99466*10^-22 g
covert to moles 3.99466*10^-22 g * 1 mol / 239.82 g = 1.6657 *10^-24 mol
convert to number of units

1.6657 *10^-24 mol * 6.23*10^23 units/mol = 1.04

385 pm = 3.85*10^(-8) cm

The volume of the unit cell is the cube of that, which is 5.71*10^(-23) cm^3. Since the ratio of mass to volume (i.e. the density) must be the same no matter what amount of TlCl you have, you can say:
7 = x/(5.71*10^(-23)), where x is the mass of the unit cell. Solving for x, you get 4*10^(-22) g.

The mass of a molecule of TlCl is 240 amu, which in grams is 4*10^(-22) g. The mass of the unit cell and the mass of a molecule of TlCl is the same. Therefore there is one formula unit of TlCl per unit cell.

3 0
2 years ago
A solution is prepared by condensing 4.00 l of a gas, measured at 27°c and 748 mmhg pressure, into 58.0 g of benzene. calculate
fgiga [73]
First, we are using the ideal gas law to get n the number of moles:

PV = nRT

when P is the pressure = 748 mmHg/760 = 0.984 atm

V is the volume = 4 L

R is ideal gas constant = 0.0821

T is the temperature in Kelvin = 300 K

∴ n =  0.984atm*4L/0.0821*300

       = 0.1598 moles

when the concentration = moles * (1000g / mass)

                                         = 0.1598 * (1000g / 58 g )

                                         = 2.755 M

when the freezing point = 5.5 °C

and Kf = - 5.12 °C/m

∴ the freezing point for the solution = 5.5 °C + (Kf*m)

                                                            = 5.5 °C - (5.12°C/m * 2.755m)

                                                            = -8.6 °C

8 0
2 years ago
Which of the following statements will decrease the amount of work the system could perform? (a) Add to the solution (b) Add sol
Dmitry_Shevchenko [17]

Answer:

Increase the concentration of the solution

Explanation:

Increasing the solute would increase the concentration. Increasing the solvent would decrease the concentration. For instance, if your lemonade was too tart, you would add more water to decrease the concentration

8 0
2 years ago
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