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balandron [24]
2 years ago
7

A power plant has 4 tons of coal. A ton of coal produces 2460 kilowatt hours of electricity. Is this enough to power 9 light bul

bs for a year? Explain.
Mathematics
1 answer:
Vadim26 [7]2 years ago
3 0

Answer:

Yes

Step-by-step explanation:

We will assume that each bulb is of 100 kW (kilowatt).

We will calculate how much energy in kilowatt-hours the light bulb will use per year in kilowatts, by the number of hours in a year.

We have,

100 kW = 0.1 kW so the energy consumed in one year is,

0.1 \times 8760=876.0\text {kWh}

Since there are 8760 hours in one year.

It is given that there are 9 bulbs so we need to have,

876 \times 9 = 7884 \text {kWh}

It is given that 1 ton of coal produces 2460 kWh, so 4 tons of coal will produce,

4\times 2460= 9840 \text {kWh}

We can observe that 4 tons of coal is producing 9840 kWh which is mroe than 7884 kWh. So, yes, 4 tons of coal can produce enough power to light 9 bulbs for a year.

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Humans living in highly populated areas are more inclined to _______. a. violence b. socially isolate c. appetite loss d. all of
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A hockey player strikes a hockey puck. The height of the puck increases until it reaches a maximum height of 1.5 feet, 30 feet a
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x₁ > x₂

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In the second case, the parable curve is modeled by:

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A second degree equation, solving for x₂ and dismissing the value x₂ = 0

we get:

y = 0       ⇒    x₂*( 0.08 - 0.002x₂) = 0    x₂ = 0

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3 0
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In one baseball season Peter hit twice the difference of the number of home runs Alice hit and 6. altogether,they hit 18 home ru
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<span>In a baseball season:
Peter hit = 2 (x - 6)
Total = 19 hits

X= Alex’s hit
Y = Peter’s Hit

=> Y = 2(x - 6)
=> x + y = 18
Let’s start from the second given equation:
=> x + y =18
=> y = 18 – x
Now, let’s use the first given equation to solve:
=> 18 – x = 2 (x - 6)
=> 18 – x = 2x – 12
=> -3x = -30
x = 10

Now, Let’s try:
=> Y = 2(x - 6)
=> y = 2 (10 - 6)
=> y = 2 (4)
=> y = 8

Thus, Peter hit 8 and Alice hit 10.</span>



4 0
2 years ago
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