Question

A compound contains 0.5 mole of sodium , 0.5 mole of nitrogen , and 1.0 mole of hydrogen . The empirical formula of the compound is
A NaNH

B Na2NH

C NaNH2

D Na(NH)2

Answer 1

Answer : The empirical formula of the compound is, (c) $NaNH_2$

Solution : Given,

Moles of sodium, Na = 0.5 moles

Moles of nitrogen, N = 0.5 moles

Moles of hydrogen, H = 1.0 moles

Divide the each moles value by the smallest number of moles of given element.

$\text{ Moles of Na}=\frac{0.5moles}{0.5moles}=1$

$\text{ Moles of N}=\frac{0.5moles}{0.5moles}=1$

$\text{ Moles of H}=\frac{1moles}{0.5moles}=2$

The mole ratio of the elements are,

Na : N : H = 1 : 1 : 2

The mole ratio of the element is represented by the subscripts in the empirical formula.

The empirical formula is written as, $Na_1N_1H_2$ or $NaNH_2$

Therefore, the empirical formula of the compound is, (c) $NaNH_2$

Answer 2

well im not the type thats going sit here and put all the steps just know that it is C

Hope this help