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2 years ago

If a circuit has a voltage of 250 volts and a resistance of 25 ohms, what are the amps for the current in the circuit?

Physics

2 answers:

Anna [14]2 years ago

7 0

Answer:

Given that,

Voltage (v) = 250 V ,

Resistance (R) = 25 Ω,

Determine current (I) =?

We know that from ohm's law

V = I R

I = V/R

= 250 / 25

I = 10 A

<em>Current in the circuit is 10 Amps</em>

gavmur [86]2 years ago

5 0

U=R•I=>I=U/R=250/25=10 A

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Two identical conducting spheres, A and B, sit atop insulating stands. When they are touched, 1.51 × 1013 electrons flow from sp

erma4kov [3.2K]

Answer:

A = -0.576 μC

B = 4.256 μC

Explanation:

Suppose a single electron charge is $1.6\times10^{-19}C$ . Then the total charge that is flowing from B to A is:

$1.6\times10^{-19} * 1.51 \times 10^{13} = 2.416\times10^{-6}C = 2.416 \mu C$

Let A and B be the initial charge of spheres A and B, respectively. Since the net charge is 3.68μC we have the following equation

$A + B = 3.68$ (1)

When they touch 2.416μC flows from B to A, then they are equal, so we have the following equation

$A + 2.416 = B - 2.416$

$-A + B = 2.416 + 2.416 = 4.832$ (2)

Add equation (1) to equation (2) we have

$2B = 3.68 + 4.832 = 8.512$

$B = 8.512 / 2 = 4.256 \mu C$

$A = 3.68 - B = 3.68 - 4.256 = -0.576 \mu C$

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2 years ago

A skier is moving down a snowy hill with an acceleration of 0.40 m/s2. The angle of the slope is 5.0∘ to the horizontal. What is

kirill115 [55]

Answer:

1.25377 m/s²

Explanation:

m = Mass of person

g = Acceleration due to gravity = 9.81 m/s²

$\mu$ = Coefficient of friction

$\theta$ = Slope

From Newton's second law

$mgsin\theta-f=ma\\\Rightarrow mgsin\theta-\mu mgcos\theta=ma\\\Rightarrow \mu=\frac{gsin\theta-a}{gcos\theta}\\\Rightarrow \mu=\frac{9.81\times sin5-0.4}{9.81\times cos5}\\\Rightarrow \mu=0.04655$

Applying $\mu$ to the above equation and $\theta=10^{\circ}$

$mgsin\theta-\mu mgcos\theta=ma\\\Rightarrow a=gsin\theta-\mu gcos\theta\\\Rightarrow a=9.81\times sin10-0.04655\times 9.81\times cos10\\\Rightarrow a=1.25377\ m/s^2$

The acceleration of the same skier when she is moving down a hill is 1.25377 m/s²

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2 years ago

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AlladinOne [14]

The answer to this question is:

C-"That moving clocks run slower"

Your Welcome :)

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2 years ago

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The grooved pulley of mass m is acted on by a constant force F through a cable which is wrapped securely around the exterior of

Sidana [21]

Answer:

Answer; v= 1.2654m/s

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Explanation:

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